141x Filetype PDF File size 0.86 MB Source: d10k7k7mywg42z.cloudfront.net
Solve each equation. 5x 2x − 4 1. 3 = 27 SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: 12 2y − 3 y + 1 2. 16 = 4 SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: 7-2 Solving Exponential Equations and Inequalities 6x x − 2 Solve each equation. 3. 2 = 32 5x 2x − 4 1. 3 = 27 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Use the Property of Equality for Exponential Functions. Functions. ANSWER: ANSWER: −10 12 x + 5 8x − 6 4. 49 = 7 2y − 3 y + 1 2. 16 = 4 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Use the Property of Equality for Exponential Functions. Functions. ANSWER: ANSWER: SCIENCE 5. Mitosis is a process in which one cell 6x x − 2 divides into two. The Escherichia coli is one of the 3. 2 = 32 fastest growing bacteria. It can reproduce itself in 15 minutes. SOLUTION: a. Write an exponential function to represent the number of cells c after t minutes. b. If you begin with one Escherichia coli cell, how many cells will there be in one hour? SOLUTION: Use the Property of Equality for Exponential a. Functions. The exponential function that represent the number of cells after t minutes is . eSolutions Manual - Powered by Cognero b. Page1 Substitute 1 for t in the function and solve for c. ANSWER: −10 ANSWER: x + 5 8x − 6 4. 49 = 7 a. SOLUTION: b. 16 cells 6. A certificate of deposit (CD) pays 2.25% annual interest compounded biweekly. If you deposit $500 into this CD, what will the balance be after 6 years? SOLUTION: Use the Property of Equality for Exponential Use the compound interest formula. Functions. Substitute $500 for P, 0.0225 for r, 26 for n and 6 for t and simplify. ANSWER: ANSWER: SCIENCE $572.23 5. Mitosis is a process in which one cell divides into two. The Escherichia coli is one of the Solve each inequality. fastest growing bacteria. It can reproduce itself in 15 2x + 6 2x – 4 minutes. 7. 4 ≤64 a. Write an exponential function to represent the number of cells c after t minutes. SOLUTION: b. If you begin with one Escherichia coli cell, how many cells will there be in one hour? SOLUTION: a. The exponential function that represent the number Use the Property of Inequality for Exponential of cells after t minutes is . Functions. b. Substitute 1 for t in the function and solve for c. ANSWER: ANSWER: a. x ≥ 4.5 b. 16 cells 6. A certificate of deposit (CD) pays 2.25% annual 8. interest compounded biweekly. If you deposit $500 into this CD, what will the balance be after 6 years? SOLUTION: SOLUTION: Use the compound interest formula. Substitute $500 for P, 0.0225 for r, 26 for n and 6 for t and simplify. Use the Property of Inequality for Exponential Functions. ANSWER: ANSWER: $572.23 Solve each inequality. Solve each equation. 4x + 2 2x + 6 2x – 4 9. 8 = 64 7. 4 ≤64 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: 0 x − 6 10. 5 = 125 ANSWER: x ≥ 4.5 SOLUTION: 8. Use the Property of Equality for Exponential SOLUTION: Functions. ANSWER: 9 Use the Property of Inequality for Exponential Functions. a + 2 3a + 1 11. 81 = 3 SOLUTION: ANSWER: Solve each equation. 4x + 2 Use the Property of Equality for Exponential 9. 8 = 64 Functions. SOLUTION: Use the Property of Equality for Exponential ANSWER: −7 Functions. b + 2 2 − 2b 12. 256 = 4 SOLUTION: ANSWER: 0 x − 6 10. 5 = 125 Use the Property of Equality for Exponential SOLUTION: Functions. Use the Property of Equality for Exponential Functions. ANSWER: −1 3c + 1 3c − 1 13. 9 = 27 ANSWER: 9 SOLUTION: a + 2 3a + 1 11. 81 = 3 SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: ANSWER: −7 2y + 4 y + 1 b + 2 2 − 2b 14. 8 = 16 12. 256 = 4 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Use the Property of Equality for Exponential Functions. Functions. ANSWER: ANSWER: −4 −1 3c + 1 3c − 1 13. 9 = 27 15. CCSS MODELINGIn 2009, My-Lien received $10,000 from her grandmother. Her parents invested SOLUTION: all of the money, and by 2021, the amount will have grown to $16,960. a. Write an exponential function that could be used to model the money y. Write the function in terms of x, the number of years since 2009. b. Assume that the amount of money continues to Use the Property of Equality for Exponential grow at the same rate. What would be the balance in Functions. the account in 2031? SOLUTION: a. Substitute 16780 for y 10000 for a and 12 for x in the exponential function and simplify. ANSWER: 2y + 4 y + 1 14. 8 = 16 The exponential function that models the situation SOLUTION: is . b. Substitute 22 for x in the modeled function and solve for y. Use the Property of Equality for Exponential Functions. ANSWER: x a . y = 10,000(1.045) b . about $26,336.52 ANSWER: Write an exponential function for the graph that −4 passes through the given points. 16. (0, 6.4) and (3, 100) 15. CCSS MODELINGIn 2009, My-Lien received $10,000 from her grandmother. Her parents invested all of the money, and by 2021, the amount will have SOLUTION: grown to $16,960. Substitute 100 for y and 6.4 for a and 3 for x into an a. Write an exponential function that could be used to exponential function and determine the value of b. model the money y. Write the function in terms of x, the number of years since 2009. b. Assume that the amount of money continues to grow at the same rate. What would be the balance in the account in 2031? SOLUTION: a. Substitute 16780 for y 10000 for a and 12 for x in the An exponential function that passes through the given exponential function and simplify. points is . ANSWER: x y = 6.4(2.5) 17. (0, 256) and (4, 81) The exponential function that models the situation SOLUTION: is . Substitute 81 for y and 256 for a and 4 for x into an exponential function and determine the value of b. b. Substitute 22 for x in the modeled function and solve for y. ANSWER: An exponential function that passes through the given x a . . y = 10,000(1.045) points is b . about $26,336.52 Write an exponential function for the graph that ANSWER: x y = 256(0.75) passes through the given points. 16. (0, 6.4) and (3, 100) 18. (0, 128) and (5, 371,293) SOLUTION: Substitute 100 for y and 6.4 for a and 3 for x into an SOLUTION: exponential function and determine the value of b. Substitute 371293 for y and 128 for a and 5 for x into an exponential function and determine the value of b. An exponential function that passes through the given An exponential function that passes through the given points is . points is . ANSWER: x ANSWER: y = 6.4(2.5) x y = 128(4.926) 17. (0, 256) and (4, 81) 19. (0, 144), and (4, 21,609) SOLUTION: SOLUTION: Substitute 81 for y and 256 for a and 4 for x into an Substitute 21609 for y and 144 for a and 4 for x into exponential function and determine the value of b. an exponential function and determine the value of b. An exponential function that passes through the given An exponential function that passes through the given points is . points is . ANSWER: ANSWER: x x y = 256(0.75) y = 144(3.5) 18. (0, 128) and (5, 371,293) 20. Find the balance of an account after 7 years if $700 is deposited into an account paying 4.3% interest SOLUTION: compounded monthly. Substitute 371293 for y and 128 for a and 5 for x into an exponential function and determine the value of b. SOLUTION: Use the compound interest formula. Substitute $700 for P, 0.043 for r, 12 for n and 7 for t and simplify. An exponential function that passes through the given points is . ANSWER: ANSWER: $945.34 x y = 128(4.926) 21. Determine how much is in a retirement account after 19. (0, 144), and (4, 21,609) 20 years if $5000 was invested at 6.05% interest compounded weekly. SOLUTION: Substitute 21609 for y and 144 for a and 4 for x into SOLUTION: an exponential function and determine the value of b. Use the compound interest formula. Substitute $5000 for P, 0.0605 for r, 52 for n and 20 for t and simplify. An exponential function that passes through the given points is . ANSWER: $16,755.63 ANSWER: 22. A savings account offers 0.7% interest compounded x y = 144(3.5) bimonthly. If $110 is deposited in this account, what 20. Find the balance of an account after 7 years if $700 will the balance be after 15 years? is deposited into an account paying 4.3% interest SOLUTION: compounded monthly. Use the compound interest formula. Substitute $110 for P, 0.007 for r, 6 for n and 15 for t SOLUTION: and simplify. Use the compound interest formula. Substitute $700 for P, 0.043 for r, 12 for n and 7 for t and simplify. ANSWER: $122.17 ANSWER: 23. A college savings account pays 13.2% annual $945.34 interest compounded semiannually. What is the 21. Determine how much is in a retirement account after balance of an account after 12 years if $21,000 was 20 years if $5000 was invested at 6.05% interest initially deposited? compounded weekly. SOLUTION: Use the compound interest formula. SOLUTION: Substitute $21,000 for P, 0.132 for r, 2 for n and 12 Use the compound interest formula. for t and simplify. Substitute $5000 for P, 0.0605 for r, 52 for n and 20 for t and simplify. ANSWER: $97,362.61 ANSWER: $16,755.63 Solve each inequality. 22. A savings account offers 0.7% interest compounded 24. bimonthly. If $110 is deposited in this account, what will the balance be after 15 years? SOLUTION: SOLUTION: Use the compound interest formula. Substitute $110 for P, 0.007 for r, 6 for n and 15 for t Use the Property of Inequality for Exponential and simplify. Functions. ANSWER: ANSWER: 25. $122.17 SOLUTION: 23. A college savings account pays 13.2% annual interest compounded semiannually. What is the balance of an account after 12 years if $21,000 was initially deposited? Use the Property of Inequality for Exponential Functions. SOLUTION: Use the compound interest formula. Substitute $21,000 for P, 0.132 for r, 2 for n and 12 for t and simplify. ANSWER: 26. ANSWER: $97,362.61 SOLUTION: Solve each inequality. 24. SOLUTION: Use the Property of Inequality for Exponential Use the Property of Inequality for Exponential Functions. Functions. ANSWER: ANSWER: 25. SOLUTION: 27. Use the Property of Inequality for Exponential SOLUTION: Functions. Use the Property of Inequality for Exponential Functions. ANSWER: 26. ANSWER: SOLUTION: 28. SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: ANSWER: 27. SOLUTION: 29. SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: 28. SOLUTION: ANSWER: 30. SCIENCEA mug of hot chocolate is 90°C at time t = 0. It is surrounded by air at a constant temperature of 20°C. If stirred steadily, its temperature in Celsius −t after t minutes will be y(t) = 20 + 70(1.071) . a. Find the temperature of the hot chocolate after 15 Use the Property of Inequality for Exponential minutes. Functions. b. Find the temperature of the hot chocolate after 30 minutes. c. The optimum drinking temperature is 60°C. Will the mug of hot chocolate be at or below this temperature after 10 minutes? SOLUTION: ANSWER: a. Substitute 15 for t in the equation and simplify. 29. b. SOLUTION: Substitute 30 for t in the equation and simplify. c. Substitute 10 for t in the equation and simplify. So, temperature of the hot chocolate will be below Use the Property of Inequality for Exponential Functions. 60°C after 10 minutes. ANSWER: a . 45.02° C b . 28.94° C c. below 31. ANIMALSStudies show that an animal will defend a territory, with area in square yards, that is directly ANSWER: proportional to the 1.31 power of the animal’s weight in pounds. a. If a 45-pound beaver will defend 170 square yards, 30. SCIENCEA mug of hot chocolate is 90°C at time t write an equation for the area a defended by a = 0. It is surrounded by air at a constant temperature beaver weighing w pounds. of 20°C. If stirred steadily, its temperature in Celsius b. Scientists believe that thousands of years ago, the −t beaver’s ancestors were 11 feet long and weighed after t minutes will be y(t) = 20 + 70(1.071) . 430 pounds. Use your equation to determine the area a. Find the temperature of the hot chocolate after 15 defended by these animals. minutes. b. Find the temperature of the hot chocolate after 30 minutes. SOLUTION: a. c. The optimum drinking temperature is 60°C. Will Substitute 170 for y, 45 for b, and 1.31 for x in the the mug of hot chocolate be at or below this exponential function. temperature after 10 minutes? SOLUTION: a. Substitute 15 for t in the equation and simplify. The equation for the area a defended by a beaver b. weighting w pounds is Substitute 30 for t in the equation and simplify. b. Substitute 430 for w in the equation and solve for y. c. Substitute 10 for t in the equation and simplify. ANSWER: So, temperature of the hot chocolate will be below a 1.31 . a = 1.16w 2 60°C after 10 minutes. b . about 3268 yd ANSWER: Solve each equation. a . 45.02° C b . 28.94° C c 32. . below SOLUTION: 31. ANIMALSStudies show that an animal will defend a territory, with area in square yards, that is directly proportional to the 1.31 power of the animal’s weight in pounds. a. If a 45-pound beaver will defend 170 square yards, write an equation for the area a defended by a beaver weighing w pounds. b. Scientists believe that thousands of years ago, the Use the Property of Equality for Exponential beaver’s ancestors were 11 feet long and weighed Functions. 430 pounds. Use your equation to determine the area defended by these animals. SOLUTION: a. Substitute 170 for y, 45 for b, and 1.31 for x in the exponential function. ANSWER: The equation for the area a defended by a beaver 33. weighting w pounds is b. SOLUTION: Substitute 430 for w in the equation and solve for y. ANSWER: Use the Property of Equality for Exponential a 1.31 . a = 1.16w Functions. b 2 . about 3268 yd Solve each equation. 32. SOLUTION: ANSWER: 34. Use the Property of Equality for Exponential Functions. SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: ANSWER: 33. −6 SOLUTION: 35. SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: ANSWER: 34. SOLUTION: 36. SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: −6 Use the Property of Equality for Exponential Functions. 35. SOLUTION: ANSWER: Use the Property of Equality for Exponential Functions. 37. SOLUTION: ANSWER: Use the Property of Equality for Exponential Functions. 36. SOLUTION: ANSWER: 1 38. CCSS MODELINGIn 1950, the world population was about 2.556 billion. By 1980, it had increased to about 4.458 billion. a. x Write an exponential function of the form y = ab that could be used to model the world population y in billions for 1950 to 1980. Write the equation in terms Use the Property of Equality for Exponential of x, the number of years since 1950. (Round the Functions. value of b to the nearest ten-thousandth.) b. Suppose the population continued to grow at that rate. Estimate the population in 2000. c. In 2000, the population of the world was about 6.08 billion. Compare your estimate to the actual population. d. Use the equation you wrote in Part a to estimate the world population in the year 2020. How accurate ANSWER: do you think the estimate is? Explain your reasoning. SOLUTION: a. Substitute 4.458 for y, 2.556 for a, and 30 for x in the 37. exponential function and solve for b. SOLUTION: The exponential function that model the situation is . Use the Property of Equality for Exponential b. Functions. Substitute 50 for x in the equation and simplify. c. The prediction was about 375 million greater than ANSWER: the actual population. 1 d. Substitute 70 for x in the equation and simplify. 38. CCSS MODELINGIn 1950, the world population was about 2.556 billion. By 1980, it had increased to about 4.458 billion. a. x Write an exponential function of the form y = ab that could be used to model the world population y in billions for 1950 to 1980. Write the equation in terms Because the prediction for 2000 was greater than the of x, the number of years since 1950. (Round the actual population, this prediction for 2020 is probably value of b to the nearest ten-thousandth.) even higher than the actual population will be at the b. Suppose the population continued to grow at that time. rate. Estimate the population in 2000. ANSWER: c. In 2000, the population of the world was about x 6.08 billion. Compare your estimate to the actual a population. . y = 2.556(1.0187) b d. Use the equation you wrote in Part a to estimate . 6.455 billion the world population in the year 2020. How accurate c. The prediction was about 375 million greater than do you think the estimate is? Explain your reasoning. the actual. d . About 9.3498 billion; because the prediction for 2000 was greater than the actual population, this SOLUTION: prediction is probably even higher than the actual a. population will be at the time. Substitute 4.458 for y, 2.556 for a, and 30 for x in the exponential function and solve for b. 39. TREES The diameter of the base of a tree trunk in centimeters varies directly with the power of its height in meters. a. A young sequoia tree is 6 meters tall, and the diameter of its base is 19.1 centimeters. Use this The exponential function that model the situation is information to write an equation for the diameter d of . the base of a sequoia tree if its height is h meters high b. b. The General Sherman Tree in Sequoia National Substitute 50 for x in the equation and simplify. Park, California, is approximately 84 meters tall. Find the diameter of the General Sherman Tree at its base. SOLUTION: c. The prediction was about 375 million greater than a. the actual population. The equation that represent the situation is d. Substitute 70 for x in the equation and simplify. . b. Substitute 84 for h in the equation and solve for d. Because the prediction for 2000 was greater than the actual population, this prediction for 2020 is probably even higher than the actual population will be at the The diameter of the General Sherman Tree at its time. base is about 1001 cm. ANSWER: ANSWER: x a . y = 2.556(1.0187) a. b . 6.455 billion b c. The prediction was about 375 million greater than . about 1001 cm the actual. d 40. FINANCIAL LITERACYMrs. Jackson has two . About 9.3498 billion; because the prediction for different retirement investment plans from which to 2000 was greater than the actual population, this choose. prediction is probably even higher than the actual a. Write equations for Option A and Option B given population will be at the time. the minimum deposits. 39. TREES The diameter of the base of a tree trunk in b. Draw a graph to show the balances for each investment option after t years. centimeters varies directly with the power of its c. Explain whether Option A or Option B is the height in meters. better investment choice. a. A young sequoia tree is 6 meters tall, and the diameter of its base is 19.1 centimeters. Use this information to write an equation for the diameter d of the base of a sequoia tree if its height is h meters high b. The General Sherman Tree in Sequoia National Park, California, is approximately 84 meters tall. Find the diameter of the General Sherman Tree at its base. SOLUTION: a. SOLUTION: Use the compound interest formula. a. The equation that represents Option A The equation that represent the situation is . is . b. The equation that represents Option B Substitute 84 for h in the equation and solve for d. is b. The graph that shows the balances for each investment option after t years: The diameter of the General Sherman Tree at its base is about 1001 cm. ANSWER: a. b . about 1001 cm 40. FINANCIAL LITERACYMrs. Jackson has two different retirement investment plans from which to choose. a. Write equations for Option A and Option B given the minimum deposits. b. Draw a graph to show the balances for each investment option after t years. c. c. Explain whether Option A or Option B is the During the first 22 years, Option B is the better better investment choice. choice because the total is greater than that of Option A. However, after about 22 years, the balance of Option A exceeds that of Option B, so Option A is the better choice. ANSWER: a. b. SOLUTION: a. Use the compound interest formula. The equation that represents Option A is . The equation that represents Option B is b. The graph that shows the balances for each investment option after t years: Sample answer: c. During the first 22 years, Option B is the better choice because the total is greater than that of Option A. However, after about 22 years, the balance of Option A exceeds that of Option B, so Option A is the better choice. 41. MULTIPLE REPRESENTATIONSIn this problem, you will explore the rapid increase of an exponential function. A large sheet of paper is cut in half, and one of the resulting pieces is placed on top of the other. Then the pieces in the stack are cut in half and placed on top of each other. Suppose this procedure is repeated several times. a. CONCRETE Perform this activity and count the number of sheets in the stack after the first cut. How many pieces will there be after the second cut? How c. many pieces after the third cut? How many pieces During the first 22 years, Option B is the better after the fourth cut? choice because the total is greater than that of b. TABULAR Option A. However, after about 22 years, the Record your results in a table. c. SYMBOLIC balance of Option A exceeds that of Option B, so Use the pattern in the table to write Option A is the better choice. an equation for the number of pieces in the stack after x cuts. ANSWER: d. ANALYTICAL The thickness of ordinary paper a. is about 0.003 inch. Write an equation for the thickness of the stack of paper after x cuts. e.ANALYTICAL b. How thick will the stack of paper be after 30 cuts? SOLUTION: a. There will be 2, 4, 8, 16 pieces after the first, second, third and fourth cut respectively. b. c. Sample answer: The equation that represent the situation is c. During the first 22 years, Option d. B is the better choice because the total is greater Substitute 0.003 for a and 2 for b in the exponential than that of Option A. However, after about 22 function. years, the balance of Option A exceeds that of Option B, so Option A is the better choice. 41. MULTIPLE REPRESENTATIONSIn this problem, you will explore the rapid increase of an e. exponential function. A large sheet of paper is cut in Substitute 30 for x in the equation and half, and one of the resulting pieces is placed on top simplify. of the other. Then the pieces in the stack are cut in half and placed on top of each other. Suppose this procedure is repeated several times. a. CONCRETE Perform this activity and count the number of sheets in the stack after the first cut. How The thickness of the stack of paper after 30 cuts is many pieces will there be after the second cut? How about 3221225.47 in. many pieces after the third cut? How many pieces after the fourth cut? b. TABULAR ANSWER: Record your results in a table. a. 2, 4, 8, 16 c. SYMBOLIC Use the pattern in the table to write b an equation for the number of pieces in the stack . after x cuts. d. ANALYTICAL The thickness of ordinary paper is about 0.003 inch. Write an equation for the thickness of the stack of paper after x cuts. e.ANALYTICAL How thick will the stack of paper be after 30 cuts? x c. y = 2 x SOLUTION: d . y = 0.003(2) a. e. about 3,221,225.47 in. There will be 2, 4, 8, 16 pieces after the first, second, third and fourth cut respectively. 42. WRITING IN MATHIn a problem about b. compound interest, describe what happens as the compounding period becomes more frequent while the principal and overall time remain the same. SOLUTION: Sample answer: The more frequently interest is compounded, the higher the account balance becomes. c. The equation that represent the situation is d. ANSWER: Substitute 0.003 for a and 2 for b in the exponential Sample answer: The more frequently interest is function. compounded, the higher the account balance becomes. x − ERROR ANALYSIS 43. Beth and Liz are solving 6 3 −x − 1 e. > 36 . Is either of them correct? Explain your Substitute 30 for x in the equation and reasoning. simplify. The thickness of the stack of paper after 30 cuts is about 3221225.47 in. ANSWER: a. 2, 4, 8, 16 b . x c. y = 2 x d . y = 0.003(2) e. about 3,221,225.47 in. 42. WRITING IN MATHIn a problem about compound interest, describe what happens as the compounding period becomes more frequent while the principal and overall time remain the same. SOLUTION: Sample answer: Beth; Liz added the exponents SOLUTION: instead of multiplying them when taking the power of Sample answer: The more frequently interest is compounded, the higher the account balance a power. becomes. ANSWER: Sample answer: Beth; Liz added the exponents ANSWER: instead of multiplying them when taking the power of Sample answer: The more frequently interest is compounded, the higher the account balance a power. becomes. 18 18 18 44. CHALLENGESolve for x: 16 + 16 + 16 + x − 18 18 x ERROR ANALYSIS 16 + 16 = 4 . 43. Beth and Liz are solving 6 3 > 36−x − 1. Is either of them correct? Explain your reasoning. SOLUTION: ANSWER: 37.1610 45. OPEN ENDEDWhat would be a more beneficial change to a 5-year loan at 8% interest compounded monthly: reducing the term to 4 years or reducing the interest rate to 6.5%? SOLUTION: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the 6.5%. ANSWER: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the 6.5%. SOLUTION: Sample answer: Beth; Liz added the exponents CCSS ARGUMENTS instead of multiplying them when taking the power of 46. Determine whether the following statements are sometimes, always, or a power. never true. Explain your reasoning. a. x 20x 2 > −8 for all values of x. ANSWER: Sample answer: Beth; Liz added the exponents b. The graph of an exponential growth equation is instead of multiplying them when taking the power of increasing. a power. c. The graph of an exponential decay equation is increasing. 18 18 18 44. CHALLENGESolve for x: 16 + 16 + 16 + 18 18 x SOLUTION: 16 + 16 = 4 . a. x 20x Always; 2 will always be positive, and −8 will SOLUTION: always be negative. b. Always; by definition the graph will always be increasing even if it is a small increase. c. Never; by definition the graph will always be decreasing even if it is a small decrease. ANSWER: a x 20x . Always; 2 will always be positive, and 8 will − always be negative. b . Always; by definition the graph will always be increasing even if it is a small increase. c. Never; by definition the graph will always be ANSWER: decreasing even if it is a small decrease. 37.1610 OPEN ENDEDWrite an exponential inequality with 47. 45. OPEN ENDEDWhat would be a more beneficial a solution of x 2. change to a 5-year loan at 8% interest compounded ≤ monthly: reducing the term to 4 years or reducing the interest rate to 6.5%? SOLUTION: x 2 Sample answer: 4 4 ≤ SOLUTION: Reducing the term will be more beneficial. The ANSWER: multiplier is 1.3756 for the 4-year and 1.3828 for the x 2 Sample answer: 4 4 ≤ 6.5%. 2x x + 1 2x + 2 4x + 1 PROOFShow that 27 · 81 = 3 · 9 . 48. ANSWER: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the SOLUTION: 6.5%. CCSS ARGUMENTS 46. Determine whether the following statements are sometimes, always, or never true. Explain your reasoning. a. x 20x 2 > −8 for all values of x. b. The graph of an exponential growth equation is increasing. c. The graph of an exponential decay equation is increasing. SOLUTION: ANSWER: a. x 20x Always; 2 will always be positive, and −8 will always be negative. b. Always; by definition the graph will always be increasing even if it is a small increase. c. Never; by definition the graph will always be decreasing even if it is a small decrease. ANSWER: x 20x WRITING IN MATHIf you were given the initial a 49. . Always; 2 will always be positive, and 8 will − and final amounts of a radioactive substance and the always be negative. amount of time that passes, how would you b . Always; by definition the graph will always be determine the rate at which the amount was increasing even if it is a small increase. increasing or decreasing in order to write an c. Never; by definition the graph will always be equation? decreasing even if it is a small decrease. SOLUTION: OPEN ENDEDWrite an exponential inequality with 47. Sample answer: Divide the final amount by the initial a solution of x 2. ≤ amount. If n is the number of time intervals that pass, take the nth root of the answer. SOLUTION: x 2 Sample answer: 4 4 ≤ ANSWER: Sample answer: Divide the final amount by the initial ANSWER: amount. If n is the number of time intervals that pass, x 2 Sample answer: 4 4 take the nth root of the answer. ≤ 2x x + 1 2x + 2 4x + 1 −4 = 50. 3 × 10 PROOFShow that 27 · 81 = 3 · 9 . 48. A 30,000 − SOLUTION: B 0.0003 C 120 − D 0.00003 SOLUTION: B is the correct option. ANSWER: ANSWER: B 51. Which of the following could not be a solution to 5 − 3x < 3? − F2.5 G3 H 3.5 WRITING IN MATHIf you were given the initial J 49. 4 and final amounts of a radioactive substance and the amount of time that passes, how would you SOLUTION: determine the rate at which the amount was Check the inequality by substituting 2.5 for x. increasing or decreasing in order to write an equation? SOLUTION: Sample answer: Divide the final amount by the initial amount. If n is the number of time intervals that pass, So, F is the correct option. take the nth root of the answer. ANSWER: ANSWER: F Sample answer: Divide the final amount by the initial GRIDDED RESPONSEThe three angles of a amount. If n is the number of time intervals that pass, 52. take the nth root of the answer. triangle are 3x, x + 10, and 2x − 40. Find the measure of the smallest angle in the triangle. −4 = 50. 3 × 10 A 30,000 SOLUTION: − Sum of the three angles in a triangle is 180 . B 0.0003 º C 120 − D 0.00003 SOLUTION: B is the correct option. The measure of the smallest angle in the triangle is ANSWER: 30 . º B ANSWER: 51. Which of the following could not be a solution to 5 − 30 3x < 3? − SAT/ACTWhich of the following is equivalent to 53. F2.5 (x)(x)(x)(x) for all x? G3 H 3.5 J A x + 4 4 B 4 x SOLUTION: C 2x2 Check the inequality by substituting 2.5 for x. D 4x2 4 E x SOLUTION: So, F is the correct option. ANSWER: F E is the correct choice. ANSWER: GRIDDED RESPONSEThe three angles of a 52. E triangle are 3x, x + 10, and 2x 40. Find the measure − of the smallest angle in the triangle. Graph each function. x SOLUTION: y = 2(3) Sum of the three angles in a triangle is 180 . 54. º SOLUTION: Make a table of values. Then plot the points and sketch the graph. The measure of the smallest angle in the triangle is 30 . º ANSWER: 30 SAT/ACT Which of the following is equivalent to 53. (x)(x)(x)(x) for all x? A x + 4 B 4x C 2x2 D 4x2 ANSWER: E 4 x SOLUTION: E is the correct choice. ANSWER: E x y = 5(2) Graph each function. 55. x y = 2(3) 54. SOLUTION: Make a table of values. Then plot the points and SOLUTION: sketch the graph. Make a table of values. Then plot the points and sketch the graph. ANSWER: ANSWER: x 56. y = 5(2) 55. SOLUTION: SOLUTION: Make a table of values. Then plot the points and Make a table of values. Then plot the points and sketch the graph. sketch the graph. ANSWER: ANSWER: Solve each equation. 57. 56. SOLUTION: SOLUTION: Make a table of values. Then plot the points and sketch the graph. ANSWER: 4 58. SOLUTION: ANSWER: 18 59. ANSWER: SOLUTION: ANSWER: Solve each equation. 8.5 57. 60. SOLUTION: SOLUTION: ANSWER: 4 The square root of x cannot be negative, so there is no solution. 58. ANSWER: SOLUTION: no solution 61. SOLUTION: ANSWER: 18 59. ANSWER: SOLUTION: 5 62. SOLUTION: ANSWER: 8.5 60. SOLUTION: ANSWER: 20 − 63. SOLUTION: The square root of x cannot be negative, so there is no solution. ANSWER: no solution 61. ANSWER: SOLUTION: 5 64. SOLUTION: ANSWER: 5 62. SOLUTION: ANSWER: 65. SOLUTION: ANSWER: 20 − 63. SOLUTION: ANSWER: 1 − SALES A salesperson earns $10 an hour plus a 10% 66. commission on sales. Write a function to describe the salesperson’s income. If the salesperson wants to earn $1000 in a 40-hour week, what should his sales be? ANSWER: 5 SOLUTION: Let I be the income of the salesperson and m be his 64. sales. The function that represent the situation is SOLUTION: . Substitute 1000 for I in the equation and solve for m. ANSWER: I(m) = 400 + 0.1m; $6000 STATE FAIRA dairy makes three types of 67. cheese cheddar, Monterey Jack, and Swiss and — — ANSWER: sells the cheese in three booths at the state fair. At the beginning of one day, the first booth received x pounds of each type of cheese. The second booth received y pounds of each type of cheese, and the third booth received z pounds of each type of cheese. 65. By the end of the day, the dairy had sold 131 pounds SOLUTION: of cheddar, 291 pounds of Monterey Jack, and 232 pounds of Swiss. The table below shows the percent of the cheese delivered in the morning that was sold at each booth. How many pounds of cheddar cheese did each booth receive in the morning? ANSWER: 1 − SOLUTION: SALES A salesperson earns $10 an hour plus a 10% The system of equations that represent the situation: 66. commission on sales. Write a function to describe the salesperson s income. If the salesperson wants to ’ earn $1000 in a 40-hour week, what should his sales be? SOLUTION: Let I be the income of the salesperson and m be his Eliminate the variable x by using two pairs of sales. equations. The function that represent the situation is . Subtract (1) and (2). Substitute 1000 for I in the equation and solve for m. ANSWER: Multiply (2) by 3 and (3) by 4 and subtract both the I(m) = 400 + 0.1m; $6000 equations. STATE FAIRA dairy makes three types of 67. cheese cheddar, Monterey Jack, and Swiss and — — sells the cheese in three booths at the state fair. At the beginning of one day, the first booth received x pounds of each type of cheese. The second booth received y pounds of each type of cheese, and the third booth received z pounds of each type of cheese. Solve the system of two equations: By the end of the day, the dairy had sold 131 pounds of cheddar, 291 pounds of Monterey Jack, and 232 pounds of Swiss. The table below shows the percent of the cheese delivered in the morning that was sold at each booth. How many pounds of cheddar cheese did each booth receive in the morning? Substitute z = 100 in the equation SOLUTION: The system of equations that represent the situation: Substitute y = 150 and z = 100 in the (1) and solve for x. Eliminate the variable x by using two pairs of equations. Subtract (1) and (2). Booth 1 has 190 lb; Booth 2 has 150 lb; Booth 3 has 100 lb. ANSWER: booth 1, 190 lb; booth 2, 150 lb; booth 3, 100 lb Find [g h](x) and [h g](x). Multiply (2) by 3 and (3) by 4 and subtract both the ◦ ◦ 68. h(x) = 2x − 1 equations. g(x) = 3x + 4 SOLUTION: Solve the system of two equations: ANSWER: 6x + 1; 6x + 7 2 Substitute z = 100 in the equation 69. h(x) = x + 2 g(x) = x − 3 SOLUTION: Substitute y = 150 and z = 100 in the (1) and solve for x. ANSWER: x2 1; x2 6x + 11 − − h(x) = x2 + 1 70. g(x) = 2x + 1 − Booth 1 has 190 lb; Booth 2 has 150 lb; Booth 3 has 100 lb. SOLUTION: ANSWER: booth 1, 190 lb; booth 2, 150 lb; booth 3, 100 lb Find [g h](x) and [h g](x). ◦ ◦ 68. h(x) = 2x − 1 g(x) = 3x + 4 ANSWER: SOLUTION: 2x2 1; 4x2 4x + 2 − − − h(x) = 5x 71. − g(x) = 3x − 5 SOLUTION: ANSWER: 6x + 1; 6x + 7 h(x) = x2 + 2 ANSWER: 69. 15x 5; 15x + 25 − − − g(x) = x − 3 3 SOLUTION: 72. h(x) = x g(x) = x − 2 SOLUTION: ANSWER: ANSWER: 2 2 3 3 2 x x 6x + 12x 8 x 1; x 6x + 11 −2; − − − − h(x) = x2 + 1 73. h(x) = x + 4 70. g(x) = 2x + 1 g(x) = | x | − SOLUTION: SOLUTION: ANSWER: | x + 4 | ; | x | + 4 ANSWER: 2x2 1; 4x2 4x + 2 − − − h(x) = 5x 71. − g(x) = 3x − 5 SOLUTION: ANSWER: 15x 5; 15x + 25 − − − h(x) = x3 72. g(x) = x − 2 SOLUTION: ANSWER: 3 3 2 x x 6x + 12x 8 −2; − − 73. h(x) = x + 4 g(x) = | x | SOLUTION: ANSWER: | x + 4 | ; | x | + 4 Solve each equation. 5x 2x − 4 1. 3 = 27 SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: 12 2y − 3 y + 1 2. 16 = 4 SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: 6x x − 2 3. 2 = 32 Solve each equation. 5x 2x − 4 SOLUTION: 1. 3 = 27 SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: −10 ANSWER: x + 5 8x − 6 12 4. 49 = 7 SOLUTION: 2y − 3 y + 1 2. 16 = 4 SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: ANSWER: SCIENCE 5. Mitosis is a process in which one cell divides into two. The Escherichia coli is one of the fastest growing bacteria. It can reproduce itself in 15 6x x − 2 minutes. 3. 2 = 32 a. Write an exponential function to represent the number of cells c after t minutes. SOLUTION: b. If you begin with one Escherichia coli cell, how many cells will there be in one hour? SOLUTION: a. The exponential function that represent the number Use the Property of Equality for Exponential of cells after t minutes is . Functions. b. Substitute 1 for t in the function and solve for c. ANSWER: −10 ANSWER: a. x + 5 8x − 6 4. 49 = 7 b. 16 cells SOLUTION: 6. A certificate of deposit (CD) pays 2.25% annual interest compounded biweekly. If you deposit $500 into this CD, what will the balance be after 6 years? SOLUTION: Use the compound interest formula. Use the Property of Equality for Exponential Substitute $500 for P, 0.0225 for r, 26 for n and 6 for Functions. t and simplify. ANSWER: 7-2 Solving Exponential Equations and Inequalities ANSWER: $572.23 SCIENCE Solve each inequality. 5. Mitosis is a process in which one cell divides into two. The Escherichia coli is one of the 2x + 6 2x – 4 fastest growing bacteria. It can reproduce itself in 15 7. 4 ≤64 minutes. SOLUTION: a. Write an exponential function to represent the number of cells c after t minutes. b. If you begin with one Escherichia coli cell, how many cells will there be in one hour? SOLUTION: a. Use the Property of Inequality for Exponential The exponential function that represent the number Functions. of cells after t minutes is . b. Substitute 1 for t in the function and solve for c. ANSWER: ANSWER: x ≥ 4.5 a. b. 16 cells 8. 6. A certificate of deposit (CD) pays 2.25% annual interest compounded biweekly. If you deposit $500 SOLUTION: into this CD, what will the balance be after 6 years? SOLUTION: Use the compound interest formula. Substitute $500 for P, 0.0225 for r, 26 for n and 6 for t and simplify. Use the Property of Inequality for Exponential Functions. ANSWER: ANSWER: Solve each equation. $572.23 4x + 2 9. 8 = 64 Solve each inequality. 2x + 6 2x – 4 SOLUTION: 7. 4 ≤64 SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Inequality for Exponential eSolutions Manual - Powered by Cognero Page2 Functions. ANSWER: 0 x − 6 10. 5 = 125 ANSWER: SOLUTION: x ≥ 4.5 8. Use the Property of Equality for Exponential Functions. SOLUTION: ANSWER: 9 Use the Property of Inequality for Exponential a + 2 3a + 1 Functions. 11. 81 = 3 SOLUTION: ANSWER: Solve each equation. Use the Property of Equality for Exponential 4x + 2 Functions. 9. 8 = 64 SOLUTION: ANSWER: −7 Use the Property of Equality for Exponential Functions. b + 2 2 − 2b 12. 256 = 4 SOLUTION: ANSWER: 0 x − 6 Use the Property of Equality for Exponential 10. 5 = 125 Functions. SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: −1 3c + 1 3c − 1 13. 9 = 27 SOLUTION: ANSWER: 9 a + 2 3a + 1 11. 81 = 3 SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: ANSWER: −7 2y + 4 y + 1 14. 8 = 16 b + 2 2 − 2b 12. 256 = 4 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: −4 ANSWER: −1 15. CCSS MODELINGIn 2009, My-Lien received 3c + 1 3c − 1 $10,000 from her grandmother. Her parents invested 13. 9 = 27 all of the money, and by 2021, the amount will have grown to $16,960. SOLUTION: a. Write an exponential function that could be used to model the money y. Write the function in terms of x, the number of years since 2009. b. Assume that the amount of money continues to grow at the same rate. What would be the balance in the account in 2031? Use the Property of Equality for Exponential Functions. SOLUTION: a. Substitute 16780 for y 10000 for a and 12 for x in the exponential function and simplify. ANSWER: 2y + 4 y + 1 The exponential function that models the situation 14. 8 = 16 is . SOLUTION: b. Substitute 22 for x in the modeled function and solve for y. Use the Property of Equality for Exponential Functions. ANSWER: x a . y = 10,000(1.045) b . about $26,336.52 Write an exponential function for the graph that ANSWER: passes through the given points. −4 16. (0, 6.4) and (3, 100) SOLUTION: 15. CCSS MODELINGIn 2009, My-Lien received Substitute 100 for y and 6.4 for a and 3 for x into an $10,000 from her grandmother. Her parents invested exponential function and determine the value of b. all of the money, and by 2021, the amount will have grown to $16,960. a. Write an exponential function that could be used to model the money y. Write the function in terms of x, the number of years since 2009. b. Assume that the amount of money continues to grow at the same rate. What would be the balance in the account in 2031? SOLUTION: a. An exponential function that passes through the given Substitute 16780 for y 10000 for a and 12 for x in the points is . exponential function and simplify. ANSWER: x y = 6.4(2.5) 17. (0, 256) and (4, 81) SOLUTION: Substitute 81 for y and 256 for a and 4 for x into an The exponential function that models the situation exponential function and determine the value of b. is . b. Substitute 22 for x in the modeled function and solve for y. An exponential function that passes through the given points is . ANSWER: x a . y = 10,000(1.045) b ANSWER: . about $26,336.52 x y = 256(0.75) Write an exponential function for the graph that 18. (0, 128) and (5, 371,293) passes through the given points. 16. (0, 6.4) and (3, 100) SOLUTION: SOLUTION: Substitute 371293 for y and 128 for a and 5 for x into Substitute 100 for y and 6.4 for a and 3 for x into an an exponential function and determine the value of b. exponential function and determine the value of b. An exponential function that passes through the given An exponential function that passes through the given points is . points is . ANSWER: x ANSWER: y = 128(4.926) x y = 6.4(2.5) 19. (0, 144), and (4, 21,609) 17. (0, 256) and (4, 81) SOLUTION: Substitute 21609 for y and 144 for a and 4 for x into SOLUTION: an exponential function and determine the value of b. Substitute 81 for y and 256 for a and 4 for x into an exponential function and determine the value of b. An exponential function that passes through the given An exponential function that passes through the given points is . points is . ANSWER: x y = 144(3.5) ANSWER: x y = 256(0.75) 20. Find the balance of an account after 7 years if $700 18. (0, 128) and (5, 371,293) is deposited into an account paying 4.3% interest compounded monthly. SOLUTION: Substitute 371293 for y and 128 for a and 5 for x into SOLUTION: an exponential function and determine the value of b. Use the compound interest formula. Substitute $700 for P, 0.043 for r, 12 for n and 7 for t and simplify. An exponential function that passes through the given points is . ANSWER: $945.34 ANSWER: 21. Determine how much is in a retirement account after x y = 128(4.926) 20 years if $5000 was invested at 6.05% interest compounded weekly. 19. (0, 144), and (4, 21,609) SOLUTION: SOLUTION: Use the compound interest formula. Substitute 21609 for y and 144 for a and 4 for x into Substitute $5000 for P, 0.0605 for r, 52 for n and 20 an exponential function and determine the value of b. for t and simplify. An exponential function that passes through the given ANSWER: points is . $16,755.63 22. A savings account offers 0.7% interest compounded ANSWER: bimonthly. If $110 is deposited in this account, what x will the balance be after 15 years? y = 144(3.5) 20. Find the balance of an account after 7 years if $700 SOLUTION: is deposited into an account paying 4.3% interest Use the compound interest formula. compounded monthly. Substitute $110 for P, 0.007 for r, 6 for n and 15 for t and simplify. SOLUTION: Use the compound interest formula. Substitute $700 for P, 0.043 for r, 12 for n and 7 for t and simplify. ANSWER: $122.17 23. A college savings account pays 13.2% annual interest compounded semiannually. What is the ANSWER: balance of an account after 12 years if $21,000 was $945.34 initially deposited? 21. Determine how much is in a retirement account after 20 years if $5000 was invested at 6.05% interest SOLUTION: compounded weekly. Use the compound interest formula. Substitute $21,000 for P, 0.132 for r, 2 for n and 12 SOLUTION: for t and simplify. Use the compound interest formula. Substitute $5000 for P, 0.0605 for r, 52 for n and 20 for t and simplify. ANSWER: $97,362.61 Solve each inequality. ANSWER: $16,755.63 24. 22. A savings account offers 0.7% interest compounded SOLUTION: bimonthly. If $110 is deposited in this account, what will the balance be after 15 years? SOLUTION: Use the compound interest formula. Use the Property of Inequality for Exponential Substitute $110 for P, 0.007 for r, 6 for n and 15 for t Functions. and simplify. ANSWER: 25. ANSWER: SOLUTION: $122.17 23. A college savings account pays 13.2% annual interest compounded semiannually. What is the balance of an account after 12 years if $21,000 was Use the Property of Inequality for Exponential initially deposited? Functions. SOLUTION: Use the compound interest formula. Substitute $21,000 for P, 0.132 for r, 2 for n and 12 for t and simplify. ANSWER: 26. ANSWER: $97,362.61 SOLUTION: Solve each inequality. 24. SOLUTION: Use the Property of Inequality for Exponential Use the Property of Inequality for Exponential Functions. Functions. ANSWER: ANSWER: 25. SOLUTION: 27. SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: 26. ANSWER: SOLUTION: 28. SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: ANSWER: 27. 29. SOLUTION: SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: 28. ANSWER: SOLUTION: 30. SCIENCEA mug of hot chocolate is 90°C at time t = 0. It is surrounded by air at a constant temperature of 20°C. If stirred steadily, its temperature in Celsius −t after t minutes will be y(t) = 20 + 70(1.071) . a. Find the temperature of the hot chocolate after 15 minutes. Use the Property of Inequality for Exponential b. Find the temperature of the hot chocolate after 30 Functions. minutes. c. The optimum drinking temperature is 60°C. Will the mug of hot chocolate be at or below this temperature after 10 minutes? SOLUTION: a. Substitute 15 for t in the equation and simplify. ANSWER: b. 29. Substitute 30 for t in the equation and simplify. SOLUTION: c. Substitute 10 for t in the equation and simplify. So, temperature of the hot chocolate will be below 60°C after 10 minutes. Use the Property of Inequality for Exponential Functions. ANSWER: a . 45.02° C b . 28.94° C c. below 31. ANIMALSStudies show that an animal will defend a territory, with area in square yards, that is directly proportional to the 1.31 power of the animal’s weight ANSWER: in pounds. a. If a 45-pound beaver will defend 170 square yards, write an equation for the area a defended by a beaver weighing w pounds. 30. SCIENCEA mug of hot chocolate is 90°C at time t b. Scientists believe that thousands of years ago, the = 0. It is surrounded by air at a constant temperature beaver’s ancestors were 11 feet long and weighed of 20°C. If stirred steadily, its temperature in Celsius 430 pounds. Use your equation to determine the area −t after t minutes will be y(t) = 20 + 70(1.071) . defended by these animals. a. Find the temperature of the hot chocolate after 15 minutes. SOLUTION: b. Find the temperature of the hot chocolate after 30 a. minutes. Substitute 170 for y, 45 for b, and 1.31 for x in the exponential function. c. The optimum drinking temperature is 60°C. Will the mug of hot chocolate be at or below this temperature after 10 minutes? SOLUTION: a. Substitute 15 for t in the equation and simplify. The equation for the area a defended by a beaver weighting w pounds is b. b. Substitute 30 for t in the equation and simplify. Substitute 430 for w in the equation and solve for y. c. Substitute 10 for t in the equation and simplify. ANSWER: a 1.31 . a = 1.16w b 2 So, temperature of the hot chocolate will be below . about 3268 yd 60°C after 10 minutes. Solve each equation. ANSWER: a 32. . 45.02° C b . 28.94° C c. below SOLUTION: 31. ANIMALSStudies show that an animal will defend a territory, with area in square yards, that is directly proportional to the 1.31 power of the animal’s weight in pounds. a. If a 45-pound beaver will defend 170 square yards, write an equation for the area a defended by a Use the Property of Equality for Exponential beaver weighing w pounds. b. Scientists believe that thousands of years ago, the Functions. beaver’s ancestors were 11 feet long and weighed 430 pounds. Use your equation to determine the area defended by these animals. SOLUTION: a. Substitute 170 for y, 45 for b, and 1.31 for x in the exponential function. ANSWER: 33. The equation for the area a defended by a beaver weighting w pounds is SOLUTION: b. Substitute 430 for w in the equation and solve for y. Use the Property of Equality for Exponential ANSWER: Functions. a 1.31 . a = 1.16w b 2 . about 3268 yd Solve each equation. 32. ANSWER: SOLUTION: 34. SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: ANSWER: −6 33. 35. SOLUTION: SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: ANSWER: 34. SOLUTION: 36. SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: Use the Property of Equality for Exponential −6 Functions. 35. SOLUTION: ANSWER: 37. Use the Property of Equality for Exponential Functions. SOLUTION: Use the Property of Equality for Exponential ANSWER: Functions. 36. ANSWER: SOLUTION: 1 38. CCSS MODELINGIn 1950, the world population was about 2.556 billion. By 1980, it had increased to about 4.458 billion. a. x Write an exponential function of the form y = ab that could be used to model the world population y in billions for 1950 to 1980. Write the equation in terms of x, the number of years since 1950. (Round the Use the Property of Equality for Exponential value of b to the nearest ten-thousandth.) Functions. b. Suppose the population continued to grow at that rate. Estimate the population in 2000. c. In 2000, the population of the world was about 6.08 billion. Compare your estimate to the actual population. d. Use the equation you wrote in Part a to estimate the world population in the year 2020. How accurate do you think the estimate is? Explain your reasoning. ANSWER: SOLUTION: a. Substitute 4.458 for y, 2.556 for a, and 30 for x in the exponential function and solve for b. 37. SOLUTION: The exponential function that model the situation is . b. Use the Property of Equality for Exponential Substitute 50 for x in the equation and simplify. Functions. c. The prediction was about 375 million greater than the actual population. d. ANSWER: 1 Substitute 70 for x in the equation and simplify. 38. CCSS MODELINGIn 1950, the world population was about 2.556 billion. By 1980, it had increased to about 4.458 billion. a. x Write an exponential function of the form y = ab Because the prediction for 2000 was greater than the that could be used to model the world population y in actual population, this prediction for 2020 is probably billions for 1950 to 1980. Write the equation in terms even higher than the actual population will be at the of x, the number of years since 1950. (Round the time. value of b to the nearest ten-thousandth.) b. Suppose the population continued to grow at that rate. Estimate the population in 2000. ANSWER: x a . y = 2.556(1.0187) c. In 2000, the population of the world was about b 6.08 billion. Compare your estimate to the actual . 6.455 billion population. c. The prediction was about 375 million greater than d. Use the equation you wrote in Part a to estimate the actual. d the world population in the year 2020. How accurate . About 9.3498 billion; because the prediction for do you think the estimate is? Explain your reasoning. 2000 was greater than the actual population, this prediction is probably even higher than the actual SOLUTION: population will be at the time. a. Substitute 4.458 for y, 2.556 for a, and 30 for x in the 39. TREES The diameter of the base of a tree trunk in exponential function and solve for b. centimeters varies directly with the power of its height in meters. a. A young sequoia tree is 6 meters tall, and the diameter of its base is 19.1 centimeters. Use this information to write an equation for the diameter d of The exponential function that model the situation is the base of a sequoia tree if its height is h meters high . b. The General Sherman Tree in Sequoia National b. Park, California, is approximately 84 meters tall. Substitute 50 for x in the equation and simplify. Find the diameter of the General Sherman Tree at its base. SOLUTION: a. The equation that represent the situation is c. The prediction was about 375 million greater than the actual population. . d. b. Substitute 70 for x in the equation and simplify. Substitute 84 for h in the equation and solve for d. Because the prediction for 2000 was greater than the The diameter of the General Sherman Tree at its actual population, this prediction for 2020 is probably base is about 1001 cm. even higher than the actual population will be at the time. ANSWER: ANSWER: a. x a . y = 2.556(1.0187) b . about 1001 cm b . 6.455 billion c. The prediction was about 375 million greater than 40. FINANCIAL LITERACYMrs. Jackson has two the actual. different retirement investment plans from which to d choose. . About 9.3498 billion; because the prediction for 2000 was greater than the actual population, this a. Write equations for Option A and Option B given prediction is probably even higher than the actual the minimum deposits. population will be at the time. b. Draw a graph to show the balances for each 39. TREES The diameter of the base of a tree trunk in investment option after t years. c. Explain whether Option A or Option B is the centimeters varies directly with the power of its better investment choice. height in meters. a. A young sequoia tree is 6 meters tall, and the diameter of its base is 19.1 centimeters. Use this information to write an equation for the diameter d of the base of a sequoia tree if its height is h meters high b. The General Sherman Tree in Sequoia National Park, California, is approximately 84 meters tall. Find the diameter of the General Sherman Tree at its SOLUTION: base. a. Use the compound interest formula. SOLUTION: The equation that represents Option A a. is . The equation that represent the situation is . The equation that represents Option B b. Substitute 84 for h in the equation and solve for d. is b. The graph that shows the balances for each investment option after t years: The diameter of the General Sherman Tree at its base is about 1001 cm. ANSWER: a. b . about 1001 cm 40. FINANCIAL LITERACYMrs. Jackson has two different retirement investment plans from which to choose. a. Write equations for Option A and Option B given the minimum deposits. b. Draw a graph to show the balances for each c. investment option after t years. During the first 22 years, Option B is the better c. Explain whether Option A or Option B is the choice because the total is greater than that of better investment choice. Option A. However, after about 22 years, the balance of Option A exceeds that of Option B, so Option A is the better choice. ANSWER: a. b. SOLUTION: a. Use the compound interest formula. The equation that represents Option A is . The equation that represents Option B is b. Sample answer: The graph that shows the balances for each c. During the first 22 years, Option investment option after t years: B is the better choice because the total is greater than that of Option A. However, after about 22 years, the balance of Option A exceeds that of Option B, so Option A is the better choice. 41. MULTIPLE REPRESENTATIONSIn this problem, you will explore the rapid increase of an exponential function. A large sheet of paper is cut in half, and one of the resulting pieces is placed on top of the other. Then the pieces in the stack are cut in half and placed on top of each other. Suppose this procedure is repeated several times. a. CONCRETE Perform this activity and count the number of sheets in the stack after the first cut. How many pieces will there be after the second cut? How many pieces after the third cut? How many pieces c. after the fourth cut? During the first 22 years, Option B is the better b. TABULAR choice because the total is greater than that of Record your results in a table. c. SYMBOLIC Option A. However, after about 22 years, the Use the pattern in the table to write balance of Option A exceeds that of Option B, so an equation for the number of pieces in the stack Option A is the better choice. after x cuts. d. ANALYTICAL The thickness of ordinary paper is about 0.003 inch. Write an equation for the ANSWER: a. thickness of the stack of paper after x cuts. e.ANALYTICAL How thick will the stack of b. paper be after 30 cuts? SOLUTION: a. There will be 2, 4, 8, 16 pieces after the first, second, third and fourth cut respectively. b. c. The equation that represent the situation is d. Sample answer: c. During the first 22 years, Option Substitute 0.003 for a and 2 for b in the exponential B is the better choice because the total is greater function. than that of Option A. However, after about 22 years, the balance of Option A exceeds that of Option B, so Option A is the better choice. e. 41. MULTIPLE REPRESENTATIONSIn this Substitute 30 for x in the equation and problem, you will explore the rapid increase of an simplify. exponential function. A large sheet of paper is cut in half, and one of the resulting pieces is placed on top of the other. Then the pieces in the stack are cut in half and placed on top of each other. Suppose this procedure is repeated several times. a. CONCRETE The thickness of the stack of paper after 30 cuts is Perform this activity and count the about 3221225.47 in. number of sheets in the stack after the first cut. How many pieces will there be after the second cut? How many pieces after the third cut? How many pieces ANSWER: after the fourth cut? a. 2, 4, 8, 16 b b. TABULAR . Record your results in a table. c. SYMBOLIC Use the pattern in the table to write an equation for the number of pieces in the stack after x cuts. d. ANALYTICAL The thickness of ordinary paper is about 0.003 inch. Write an equation for the thickness of the stack of paper after x cuts. x c e.ANALYTICAL . y = 2 How thick will the stack of x paper be after 30 cuts? d . y = 0.003(2) e. about 3,221,225.47 in. SOLUTION: a. There will be 2, 4, 8, 16 pieces after the first, second, 42. WRITING IN MATHIn a problem about third and fourth cut respectively. compound interest, describe what happens as the b. compounding period becomes more frequent while the principal and overall time remain the same. SOLUTION: Sample answer: The more frequently interest is compounded, the higher the account balance becomes. ANSWER: c. The equation that represent the situation is Sample answer: The more frequently interest is d. compounded, the higher the account balance Substitute 0.003 for a and 2 for b in the exponential becomes. function. x − ERROR ANALYSIS 43. Beth and Liz are solving 6 3 > 36−x − 1. Is either of them correct? Explain your reasoning. e. Substitute 30 for x in the equation and simplify. The thickness of the stack of paper after 30 cuts is about 3221225.47 in. ANSWER: a. 2, 4, 8, 16 b . x c. y = 2 x d . y = 0.003(2) e. about 3,221,225.47 in. 42. WRITING IN MATHIn a problem about compound interest, describe what happens as the compounding period becomes more frequent while SOLUTION: the principal and overall time remain the same. Sample answer: Beth; Liz added the exponents instead of multiplying them when taking the power of SOLUTION: a power. Sample answer: The more frequently interest is compounded, the higher the account balance ANSWER: becomes. Sample answer: Beth; Liz added the exponents instead of multiplying them when taking the power of ANSWER: a power. Sample answer: The more frequently interest is compounded, the higher the account balance 18 18 18 becomes. 44. CHALLENGESolve for x: 16 + 16 + 16 + 18 18 x 16 + 16 = 4 . x − ERROR ANALYSIS 43. Beth and Liz are solving 6 SOLUTION: 3 > 36−x − 1. Is either of them correct? Explain your reasoning. ANSWER: 37.1610 45. OPEN ENDEDWhat would be a more beneficial change to a 5-year loan at 8% interest compounded monthly: reducing the term to 4 years or reducing the interest rate to 6.5%? SOLUTION: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the 6.5%. ANSWER: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the 6.5%. SOLUTION: CCSS ARGUMENTS 46. Determine whether the Sample answer: Beth; Liz added the exponents following statements are sometimes, always, or instead of multiplying them when taking the power of never true. Explain your reasoning. x 20x a power. a. 2 > −8 for all values of x. b. The graph of an exponential growth equation is ANSWER: increasing. Sample answer: Beth; Liz added the exponents instead of multiplying them when taking the power of c. The graph of an exponential decay equation is increasing. a power. 18 18 18 SOLUTION: 44. CHALLENGESolve for x: 16 + 16 + 16 + a. x 20x 18 18 x Always; 2 will always be positive, and −8 will 16 + 16 = 4 . always be negative. b. Always; by definition the graph will always be SOLUTION: increasing even if it is a small increase. c. Never; by definition the graph will always be decreasing even if it is a small decrease. ANSWER: a x 20x . Always; 2 will always be positive, and 8 will − always be negative. b . Always; by definition the graph will always be increasing even if it is a small increase. c. Never; by definition the graph will always be decreasing even if it is a small decrease. ANSWER: 37.1610 OPEN ENDEDWrite an exponential inequality with 47. a solution of x 2. ≤ 45. OPEN ENDEDWhat would be a more beneficial change to a 5-year loan at 8% interest compounded SOLUTION: monthly: reducing the term to 4 years or reducing the x 2 Sample answer: 4 4 interest rate to 6.5%? ≤ ANSWER: SOLUTION: x 2 Sample answer: 4 4 Reducing the term will be more beneficial. The ≤ multiplier is 1.3756 for the 4-year and 1.3828 for the 2x x + 1 2x + 2 4x + 1 6.5%. PROOFShow that 27 · 81 = 3 · 9 . 48. SOLUTION: ANSWER: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the 6.5%. CCSS ARGUMENTS 46. Determine whether the following statements are sometimes, always, or never true. Explain your reasoning. a. x 20x 2 > −8 for all values of x. b. The graph of an exponential growth equation is increasing. c. The graph of an exponential decay equation is increasing. ANSWER: SOLUTION: a. x 20x Always; 2 will always be positive, and −8 will always be negative. b. Always; by definition the graph will always be increasing even if it is a small increase. c. Never; by definition the graph will always be decreasing even if it is a small decrease. WRITING IN MATHIf you were given the initial 49. ANSWER: and final amounts of a radioactive substance and the a x 20x . Always; 2 will always be positive, and 8 will − amount of time that passes, how would you always be negative. determine the rate at which the amount was b . Always; by definition the graph will always be increasing or decreasing in order to write an increasing even if it is a small increase. equation? c. Never; by definition the graph will always be decreasing even if it is a small decrease. SOLUTION: Sample answer: Divide the final amount by the initial OPEN ENDEDWrite an exponential inequality with amount. If n is the number of time intervals that pass, 47. a solution of x 2. take the nth root of the answer. ≤ SOLUTION: ANSWER: x 2 Sample answer: Divide the final amount by the initial Sample answer: 4 4 ≤ amount. If n is the number of time intervals that pass, take the nth root of the answer. ANSWER: x 2 Sample answer: 4 4 ≤ −4 = 50. 3 × 10 A 30,000 2x x + 1 2x + 2 4x + 1 − PROOFShow that 27 · 81 = 3 · 9 . 48. B 0.0003 SOLUTION: C 120 − D 0.00003 SOLUTION: B is the correct option. ANSWER: ANSWER: B 51. Which of the following could not be a solution to 5 − 3x < 3? − F2.5 G3 H 3.5 J 4 WRITING IN MATHIf you were given the initial 49. and final amounts of a radioactive substance and the SOLUTION: amount of time that passes, how would you Check the inequality by substituting 2.5 for x. determine the rate at which the amount was increasing or decreasing in order to write an equation? SOLUTION: So, F is the correct option. Sample answer: Divide the final amount by the initial amount. If n is the number of time intervals that pass, take the nth root of the answer. ANSWER: F ANSWER: GRIDDED RESPONSEThe three angles of a Sample answer: Divide the final amount by the initial 52. amount. If n is the number of time intervals that pass, triangle are 3x, x + 10, and 2x − 40. Find the measure take the nth root of the answer. of the smallest angle in the triangle. −4 SOLUTION: = Sum of the three angles in a triangle is 180 . 50. 3 × 10 º A 30,000 − B 0.0003 C 120 − D 0.00003 SOLUTION: The measure of the smallest angle in the triangle is B is the correct option. 30 . º ANSWER: B ANSWER: 30 51. Which of the following could not be a solution to 5 − SAT/ACT Which of the following is equivalent to 3x < 3? 53. − (x)(x)(x)(x) for all x? F2.5 G3 A x + 4 H 3.5 B 4x J 4 C 2x2 2 SOLUTION: D 4x Check the inequality by substituting 2.5 for x. E 4 x SOLUTION: So, F is the correct option. E is the correct choice. ANSWER: F ANSWER: E GRIDDED RESPONSEThe three angles of a 52. triangle are 3x, x + 10, and 2x − 40. Find the measure Graph each function. of the smallest angle in the triangle. x y = 2(3) 54. SOLUTION: Sum of the three angles in a triangle is 180 . SOLUTION: º Make a table of values. Then plot the points and sketch the graph. The measure of the smallest angle in the triangle is 30 . º ANSWER: 30 SAT/ACT Which of the following is equivalent to 53. (x)(x)(x)(x) for all x? A x + 4 B 4x 2 ANSWER: C2x D 4x2 E 4 x SOLUTION: E is the correct choice. ANSWER: x E y = 5(2) 55. Graph each function. SOLUTION: x y = 2(3) Make a table of values. Then plot the points and 54. sketch the graph. SOLUTION: Make a table of values. Then plot the points and sketch the graph. ANSWER: ANSWER: 56. x y = 5(2) SOLUTION: 55. Make a table of values. Then plot the points and SOLUTION: sketch the graph. Make a table of values. Then plot the points and sketch the graph. ANSWER: ANSWER: Solve each equation. 57. SOLUTION: 56. SOLUTION: Make a table of values. Then plot the points and sketch the graph. ANSWER: 4 58. SOLUTION: ANSWER: 18 59. ANSWER: SOLUTION: ANSWER: 8.5 Solve each equation. 60. 57. SOLUTION: SOLUTION: ANSWER: The square root of x cannot be negative, so there is 4 no solution. ANSWER: 58. no solution SOLUTION: 61. SOLUTION: ANSWER: 18 ANSWER: 59. 5 SOLUTION: 62. SOLUTION: ANSWER: 8.5 60. ANSWER: SOLUTION: 20 − 63. SOLUTION: The square root of x cannot be negative, so there is no solution. ANSWER: no solution ANSWER: 61. 5 SOLUTION: 64. SOLUTION: ANSWER: 5 62. SOLUTION: ANSWER: 65. SOLUTION: ANSWER: 20 − 63. SOLUTION: ANSWER: 1 − SALES A salesperson earns $10 an hour plus a 10% 66. commission on sales. Write a function to describe the salesperson’s income. If the salesperson wants to earn $1000 in a 40-hour week, what should his sales be? ANSWER: SOLUTION: 5 Let I be the income of the salesperson and m be his sales. The function that represent the situation is 64. . SOLUTION: Substitute 1000 for I in the equation and solve for m. ANSWER: I(m) = 400 + 0.1m; $6000 STATE FAIRA dairy makes three types of 67. cheese cheddar, Monterey Jack, and Swiss and — — sells the cheese in three booths at the state fair. At ANSWER: the beginning of one day, the first booth received x pounds of each type of cheese. The second booth received y pounds of each type of cheese, and the third booth received z pounds of each type of cheese. By the end of the day, the dairy had sold 131 pounds 65. of cheddar, 291 pounds of Monterey Jack, and 232 pounds of Swiss. The table below shows the percent SOLUTION: of the cheese delivered in the morning that was sold at each booth. How many pounds of cheddar cheese did each booth receive in the morning? ANSWER: SOLUTION: 1 − The system of equations that represent the situation: SALES A salesperson earns $10 an hour plus a 10% 66. commission on sales. Write a function to describe the salesperson’s income. If the salesperson wants to earn $1000 in a 40-hour week, what should his sales be? SOLUTION: Eliminate the variable x by using two pairs of Let I be the income of the salesperson and m be his equations. sales. The function that represent the situation is Subtract (1) and (2). . Substitute 1000 for I in the equation and solve for m. Multiply (2) by 3 and (3) by 4 and subtract both the ANSWER: equations. I(m) = 400 + 0.1m; $6000 STATE FAIRA dairy makes three types of 67. cheese cheddar, Monterey Jack, and Swiss and — — sells the cheese in three booths at the state fair. At the beginning of one day, the first booth received x pounds of each type of cheese. The second booth received y pounds of each type of cheese, and the Solve the system of two equations: third booth received z pounds of each type of cheese. By the end of the day, the dairy had sold 131 pounds of cheddar, 291 pounds of Monterey Jack, and 232 pounds of Swiss. The table below shows the percent of the cheese delivered in the morning that was sold at each booth. How many pounds of cheddar cheese did each booth receive in the morning? Substitute z = 100 in the equation SOLUTION: The system of equations that represent the situation: Substitute y = 150 and z = 100 in the (1) and solve for x. Eliminate the variable x by using two pairs of equations. Booth 1 has 190 lb; Booth 2 has 150 lb; Booth 3 has Subtract (1) and (2). 100 lb. ANSWER: booth 1, 190 lb; booth 2, 150 lb; booth 3, 100 lb Find [g h](x) and [h g](x). ◦ ◦ h(x) = 2x 1 Multiply (2) by 3 and (3) by 4 and subtract both the 68. − equations. g(x) = 3x + 4 SOLUTION: Solve the system of two equations: ANSWER: 6x + 1; 6x + 7 h(x) = x2 + 2 69. Substitute z = 100 in the equation g(x) = x − 3 SOLUTION: Substitute y = 150 and z = 100 in the (1) and solve for x. ANSWER: 2 2 x 1; x 6x + 11 − − h(x) = x2 + 1 70. g(x) = 2x + 1 − SOLUTION: Booth 1 has 190 lb; Booth 2 has 150 lb; Booth 3 has 100 lb. ANSWER: booth 1, 190 lb; booth 2, 150 lb; booth 3, 100 lb Find [g h](x) and [h g](x). ◦ ◦ 68. h(x) = 2x − 1 g(x) = 3x + 4 ANSWER: 2x2 1; 4x2 4x + 2 − − − SOLUTION: h(x) = 5x 71. − g(x) = 3x − 5 SOLUTION: ANSWER: 6x + 1; 6x + 7 ANSWER: 15x 5; 15x + 25 2 − − − 69. h(x) = x + 2 3 g(x) = x − 3 h(x) = x 72. g(x) = x − 2 SOLUTION: SOLUTION: ANSWER: 3 3 2 x x 6x + 12x 8 −2; − − ANSWER: x2 1; x2 6x + 11 − − h(x) = x + 4 73. 2 g(x) = | x | 70. h(x) = x + 1 g(x) = 2x + 1 SOLUTION: − SOLUTION: ANSWER: | x + 4 | ; | x | + 4 ANSWER: 2x2 1; 4x2 4x + 2 − − − h(x) = 5x 71. − g(x) = 3x − 5 SOLUTION: ANSWER: 15x 5; 15x + 25 − − − h(x) = x3 72. g(x) = x − 2 SOLUTION: ANSWER: 3 3 2 x x 6x + 12x 8 −2; − − 73. h(x) = x + 4 g(x) = | x | SOLUTION: ANSWER: | x + 4 | ; | x | + 4 Solve each equation. 5x 2x − 4 1. 3 = 27 SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: 12 2y − 3 y + 1 2. 16 = 4 SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: 6x x − 2 3. 2 = 32 SOLUTION: Use the Property of Equality for Exponential Functions. Solve each equation. 5x 2x − 4 1. 3 = 27 SOLUTION: ANSWER: −10 x + 5 8x − 6 4. 49 = 7 Use the Property of Equality for Exponential SOLUTION: Functions. ANSWER: Use the Property of Equality for Exponential 12 Functions. 2y − 3 y + 1 2. 16 = 4 SOLUTION: ANSWER: Use the Property of Equality for Exponential Functions. SCIENCE 5. Mitosis is a process in which one cell divides into two. The Escherichia coli is one of the fastest growing bacteria. It can reproduce itself in 15 minutes. a. Write an exponential function to represent the number of cells c after t minutes. b. If you begin with one Escherichia coli cell, how many cells will there be in one hour? ANSWER: SOLUTION: a. The exponential function that represent the number 6x x − 2 of cells after t minutes is . 3. 2 = 32 b. SOLUTION: Substitute 1 for t in the function and solve for c. ANSWER: Use the Property of Equality for Exponential a. Functions. b. 16 cells 6. A certificate of deposit (CD) pays 2.25% annual interest compounded biweekly. If you deposit $500 into this CD, what will the balance be after 6 years? ANSWER: −10 SOLUTION: Use the compound interest formula. x + 5 8x − 6 Substitute $500 for P, 0.0225 for r, 26 for n and 6 for 4. 49 = 7 t and simplify. SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: $572.23 Solve each inequality. 2x + 6 2x – 4 7. 4 ≤64 SOLUTION: ANSWER: SCIENCE 5. Mitosis is a process in which one cell Use the Property of Inequality for Exponential divides into two. The Escherichia coli is one of the Functions. fastest growing bacteria. It can reproduce itself in 15 minutes. a. Write an exponential function to represent the number of cells c after t minutes. b. If you begin with one Escherichia coli cell, how many cells will there be in one hour? ANSWER: SOLUTION: a. x ≥ 4.5 The exponential function that represent the number of cells after t minutes is . b. 8. Substitute 1 for t in the function and solve for c. SOLUTION: ANSWER: a. b. 16 cells Use the Property of Inequality for Exponential 6. A certificate of deposit (CD) pays 2.25% annual Functions. interest compounded biweekly. If you deposit $500 into this CD, what will the balance be after 6 years? SOLUTION: Use the compound interest formula. Substitute $500 for P, 0.0225 for r, 26 for n and 6 for ANSWER: t and simplify. Solve each equation. 4x + 2 9. 8 = 64 SOLUTION: Use the Property of Equality for Exponential ANSWER: Functions. $572.23 Solve each inequality. 2x + 6 2x – 4 7. 4 ≤64 ANSWER: SOLUTION: 0 x − 6 10. 5 = 125 SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: x ≥ 4.5 ANSWER: 9 8. a + 2 3a + 1 11. 81 = 3 SOLUTION: SOLUTION: Use the Property of Inequality for Exponential Use the Property of Equality for Exponential Functions. Functions. ANSWER: ANSWER: 7-2 Solving Exponential Equations and Inequalities −7 Solve each equation. b + 2 2 − 2b 4x + 2 12. 256 = 4 9. 8 = 64 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Use the Property of Equality for Exponential Functions. Functions. ANSWER: 0 ANSWER: −1 x − 6 10. 5 = 125 3c + 1 3c − 1 13. 9 = 27 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: 9 a + 2 3a + 1 11. 81 = 3 SOLUTION: ANSWER: 2y + 4 y + 1 14. 8 = 16 Use the Property of Equality for Exponential Functions. SOLUTION: ANSWER: −7 Use the Property of Equality for Exponential Functions. b + 2 2 − 2b 12. 256 = 4 eSolutions Manual - Powered by Cognero Page3 SOLUTION: ANSWER: −4 Use the Property of Equality for Exponential Functions. 15. CCSS MODELINGIn 2009, My-Lien received $10,000 from her grandmother. Her parents invested all of the money, and by 2021, the amount will have grown to $16,960. a. Write an exponential function that could be used to model the money y. Write the function in terms of x, the number of years since 2009. b. Assume that the amount of money continues to ANSWER: −1 grow at the same rate. What would be the balance in the account in 2031? 3c + 1 3c − 1 13. 9 = 27 SOLUTION: a. SOLUTION: Substitute 16780 for y 10000 for a and 12 for x in the exponential function and simplify. Use the Property of Equality for Exponential Functions. The exponential function that models the situation is . b. ANSWER: Substitute 22 for x in the modeled function and solve for y. 2y + 4 y + 1 14. 8 = 16 SOLUTION: ANSWER: x a . y = 10,000(1.045) b . about $26,336.52 Write an exponential function for the graph that Use the Property of Equality for Exponential passes through the given points. Functions. 16. (0, 6.4) and (3, 100) SOLUTION: Substitute 100 for y and 6.4 for a and 3 for x into an exponential function and determine the value of b. ANSWER: −4 15. CCSS MODELINGIn 2009, My-Lien received $10,000 from her grandmother. Her parents invested all of the money, and by 2021, the amount will have grown to $16,960. An exponential function that passes through the given a. Write an exponential function that could be used to points is . model the money y. Write the function in terms of x, the number of years since 2009. b. Assume that the amount of money continues to ANSWER: x grow at the same rate. What would be the balance in y = 6.4(2.5) the account in 2031? 17. (0, 256) and (4, 81) SOLUTION: a. SOLUTION: Substitute 16780 for y 10000 for a and 12 for x in the Substitute 81 for y and 256 for a and 4 for x into an exponential function and simplify. exponential function and determine the value of b. The exponential function that models the situation is . An exponential function that passes through the given points is . b. Substitute 22 for x in the modeled function and solve ANSWER: for y. x y = 256(0.75) 18. (0, 128) and (5, 371,293) SOLUTION: Substitute 371293 for y and 128 for a and 5 for x into ANSWER: an exponential function and determine the value of b. x a . y = 10,000(1.045) b . about $26,336.52 Write an exponential function for the graph that passes through the given points. 16. (0, 6.4) and (3, 100) SOLUTION: Substitute 100 for y and 6.4 for a and 3 for x into an exponential function and determine the value of b. An exponential function that passes through the given points is . ANSWER: x y = 128(4.926) 19. (0, 144), and (4, 21,609) SOLUTION: An exponential function that passes through the given Substitute 21609 for y and 144 for a and 4 for x into points is . an exponential function and determine the value of b. ANSWER: x y = 6.4(2.5) 17. (0, 256) and (4, 81) SOLUTION: Substitute 81 for y and 256 for a and 4 for x into an An exponential function that passes through the given exponential function and determine the value of b. points is . ANSWER: x y = 144(3.5) 20. Find the balance of an account after 7 years if $700 is deposited into an account paying 4.3% interest compounded monthly. An exponential function that passes through the given SOLUTION: points is . Use the compound interest formula. Substitute $700 for P, 0.043 for r, 12 for n and 7 for t and simplify. ANSWER: x y = 256(0.75) 18. (0, 128) and (5, 371,293) SOLUTION: Substitute 371293 for y and 128 for a and 5 for x into an exponential function and determine the value of b. ANSWER: $945.34 21. Determine how much is in a retirement account after 20 years if $5000 was invested at 6.05% interest compounded weekly. SOLUTION: An exponential function that passes through the given Use the compound interest formula. points is . Substitute $5000 for P, 0.0605 for r, 52 for n and 20 for t and simplify. ANSWER: x y = 128(4.926) 19. (0, 144), and (4, 21,609) SOLUTION: Substitute 21609 for y and 144 for a and 4 for x into an exponential function and determine the value of b. ANSWER: $16,755.63 22. A savings account offers 0.7% interest compounded bimonthly. If $110 is deposited in this account, what will the balance be after 15 years? SOLUTION: Use the compound interest formula. An exponential function that passes through the given Substitute $110 for P, 0.007 for r, 6 for n and 15 for t points is . and simplify. ANSWER: x y = 144(3.5) 20. Find the balance of an account after 7 years if $700 is deposited into an account paying 4.3% interest compounded monthly. ANSWER: SOLUTION: Use the compound interest formula. $122.17 Substitute $700 for P, 0.043 for r, 12 for n and 7 for t 23. A college savings account pays 13.2% annual and simplify. interest compounded semiannually. What is the balance of an account after 12 years if $21,000 was initially deposited? SOLUTION: Use the compound interest formula. Substitute $21,000 for P, 0.132 for r, 2 for n and 12 for t and simplify. ANSWER: $945.34 21. Determine how much is in a retirement account after 20 years if $5000 was invested at 6.05% interest compounded weekly. SOLUTION: Use the compound interest formula. ANSWER: Substitute $5000 for P, 0.0605 for r, 52 for n and 20 $97,362.61 for t and simplify. Solve each inequality. 24. SOLUTION: Use the Property of Inequality for Exponential Functions. ANSWER: $16,755.63 22. A savings account offers 0.7% interest compounded bimonthly. If $110 is deposited in this account, what will the balance be after 15 years? ANSWER: SOLUTION: Use the compound interest formula. Substitute $110 for P, 0.007 for r, 6 for n and 15 for t and simplify. 25. SOLUTION: Use the Property of Inequality for Exponential Functions. ANSWER: $122.17 23. A college savings account pays 13.2% annual interest compounded semiannually. What is the balance of an account after 12 years if $21,000 was ANSWER: initially deposited? SOLUTION: Use the compound interest formula. Substitute $21,000 for P, 0.132 for r, 2 for n and 12 26. for t and simplify. SOLUTION: ANSWER: $97,362.61 Use the Property of Inequality for Exponential Solve each inequality. Functions. 24. SOLUTION: Use the Property of Inequality for Exponential ANSWER: Functions. 27. SOLUTION: ANSWER: 25. SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: ANSWER: 28. SOLUTION: 26. SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: 29. ANSWER: SOLUTION: 27. SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: 30. SCIENCEA mug of hot chocolate is 90°C at time t ANSWER: = 0. It is surrounded by air at a constant temperature of 20°C. If stirred steadily, its temperature in Celsius −t after t minutes will be y(t) = 20 + 70(1.071) . 28. a. Find the temperature of the hot chocolate after 15 minutes. SOLUTION: b. Find the temperature of the hot chocolate after 30 minutes. c. The optimum drinking temperature is 60°C. Will the mug of hot chocolate be at or below this temperature after 10 minutes? SOLUTION: a. Substitute 15 for t in the equation and simplify. Use the Property of Inequality for Exponential Functions. b. Substitute 30 for t in the equation and simplify. c. ANSWER: Substitute 10 for t in the equation and simplify. 29. So, temperature of the hot chocolate will be below 60°C after 10 minutes. SOLUTION: ANSWER: a . 45.02° C b . 28.94° C c. below 31. ANIMALSStudies show that an animal will defend a territory, with area in square yards, that is directly Use the Property of Inequality for Exponential proportional to the 1.31 power of the animal’s weight in pounds. Functions. a. If a 45-pound beaver will defend 170 square yards, write an equation for the area a defended by a beaver weighing w pounds. b. Scientists believe that thousands of years ago, the beaver’s ancestors were 11 feet long and weighed 430 pounds. Use your equation to determine the area defended by these animals. ANSWER: SOLUTION: a. Substitute 170 for y, 45 for b, and 1.31 for x in the exponential function. 30. SCIENCEA mug of hot chocolate is 90°C at time t = 0. It is surrounded by air at a constant temperature of 20°C. If stirred steadily, its temperature in Celsius −t after t minutes will be y(t) = 20 + 70(1.071) . a. Find the temperature of the hot chocolate after 15 minutes. b. Find the temperature of the hot chocolate after 30 The equation for the area a defended by a beaver minutes. weighting w pounds is c. The optimum drinking temperature is 60°C. Will b. the mug of hot chocolate be at or below this Substitute 430 for w in the equation and solve for y. temperature after 10 minutes? SOLUTION: a. Substitute 15 for t in the equation and simplify. ANSWER: a 1.31 b. . a = 1.16w b 2 Substitute 30 for t in the equation and simplify. . about 3268 yd Solve each equation. 32. c. Substitute 10 for t in the equation and simplify. SOLUTION: So, temperature of the hot chocolate will be below 60°C after 10 minutes. ANSWER: a . 45.02° C b . 28.94° C Use the Property of Equality for Exponential c. below Functions. 31. ANIMALSStudies show that an animal will defend a territory, with area in square yards, that is directly proportional to the 1.31 power of the animal’s weight in pounds. a. If a 45-pound beaver will defend 170 square yards, write an equation for the area a defended by a beaver weighing w pounds. ANSWER: b. Scientists believe that thousands of years ago, the beaver’s ancestors were 11 feet long and weighed 430 pounds. Use your equation to determine the area defended by these animals. 33. SOLUTION: a. Substitute 170 for y, 45 for b, and 1.31 for x in the exponential function. SOLUTION: The equation for the area a defended by a beaver Use the Property of Equality for Exponential weighting w pounds is Functions. b. Substitute 430 for w in the equation and solve for y. ANSWER: ANSWER: a 1.31 . a = 1.16w b 2 . about 3268 yd Solve each equation. 34. 32. SOLUTION: SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: −6 35. ANSWER: SOLUTION: 33. SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: 36. ANSWER: SOLUTION: 34. SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: −6 ANSWER: 35. 37. SOLUTION: SOLUTION: Use the Property of Equality for Exponential Use the Property of Equality for Exponential Functions. Functions. ANSWER: 1 ANSWER: 38. CCSS MODELINGIn 1950, the world population was about 2.556 billion. By 1980, it had increased to about 4.458 billion. a. x Write an exponential function of the form y = ab 36. that could be used to model the world population y in billions for 1950 to 1980. Write the equation in terms SOLUTION: of x, the number of years since 1950. (Round the value of b to the nearest ten-thousandth.) b. Suppose the population continued to grow at that rate. Estimate the population in 2000. c. In 2000, the population of the world was about 6.08 billion. Compare your estimate to the actual population. d. Use the equation you wrote in Part a to estimate the world population in the year 2020. How accurate do you think the estimate is? Explain your reasoning. Use the Property of Equality for Exponential Functions. SOLUTION: a. Substitute 4.458 for y, 2.556 for a, and 30 for x in the exponential function and solve for b. ANSWER: The exponential function that model the situation is . b. 37. Substitute 50 for x in the equation and simplify. SOLUTION: c. The prediction was about 375 million greater than the actual population. d. Use the Property of Equality for Exponential Substitute 70 for x in the equation and simplify. Functions. Because the prediction for 2000 was greater than the actual population, this prediction for 2020 is probably ANSWER: even higher than the actual population will be at the 1 time. 38. CCSS MODELINGIn 1950, the world population ANSWER: was about 2.556 billion. By 1980, it had increased to x a about 4.458 billion. . y = 2.556(1.0187) b a. x . 6.455 billion Write an exponential function of the form y = ab c. The prediction was about 375 million greater than that could be used to model the world population y in the actual. billions for 1950 to 1980. Write the equation in terms d of x, the number of years since 1950. (Round the . About 9.3498 billion; because the prediction for value of b to the nearest ten-thousandth.) 2000 was greater than the actual population, this b. Suppose the population continued to grow at that prediction is probably even higher than the actual rate. Estimate the population in 2000. population will be at the time. c. In 2000, the population of the world was about 39. TREES The diameter of the base of a tree trunk in 6.08 billion. Compare your estimate to the actual centimeters varies directly with the power of its population. d. Use the equation you wrote in Part a to estimate height in meters. the world population in the year 2020. How accurate a. A young sequoia tree is 6 meters tall, and the do you think the estimate is? Explain your reasoning. diameter of its base is 19.1 centimeters. Use this information to write an equation for the diameter d of SOLUTION: the base of a sequoia tree if its height is h meters a. Substitute 4.458 for y, 2.556 for a, and 30 for x in the high exponential function and solve for b. b. The General Sherman Tree in Sequoia National Park, California, is approximately 84 meters tall. Find the diameter of the General Sherman Tree at its base. SOLUTION: The exponential function that model the situation is a. . The equation that represent the situation is . b. b. Substitute 50 for x in the equation and simplify. Substitute 84 for h in the equation and solve for d. c. The prediction was about 375 million greater than the actual population. The diameter of the General Sherman Tree at its d. base is about 1001 cm. Substitute 70 for x in the equation and simplify. ANSWER: a. b . about 1001 cm Because the prediction for 2000 was greater than the 40. FINANCIAL LITERACYMrs. Jackson has two actual population, this prediction for 2020 is probably different retirement investment plans from which to even higher than the actual population will be at the choose. time. a. Write equations for Option A and Option B given the minimum deposits. ANSWER: b. Draw a graph to show the balances for each x a investment option after t years. . y = 2.556(1.0187) b c. Explain whether Option A or Option B is the . 6.455 billion better investment choice. c. The prediction was about 375 million greater than the actual. d . About 9.3498 billion; because the prediction for 2000 was greater than the actual population, this prediction is probably even higher than the actual population will be at the time. 39. TREES The diameter of the base of a tree trunk in centimeters varies directly with the power of its height in meters. a. A young sequoia tree is 6 meters tall, and the SOLUTION: diameter of its base is 19.1 centimeters. Use this a. information to write an equation for the diameter d of Use the compound interest formula. the base of a sequoia tree if its height is h meters The equation that represents Option A high is . b. The General Sherman Tree in Sequoia National Park, California, is approximately 84 meters tall. The equation that represents Option B Find the diameter of the General Sherman Tree at its is base. b. SOLUTION: The graph that shows the balances for each a. investment option after t years: The equation that represent the situation is . b. Substitute 84 for h in the equation and solve for d. The diameter of the General Sherman Tree at its base is about 1001 cm. ANSWER: a. c. b During the first 22 years, Option B is the better . about 1001 cm choice because the total is greater than that of Option A. However, after about 22 years, the 40. FINANCIAL LITERACYMrs. Jackson has two different retirement investment plans from which to balance of Option A exceeds that of Option B, so choose. Option A is the better choice. a. Write equations for Option A and Option B given the minimum deposits. ANSWER: b. Draw a graph to show the balances for each a. investment option after t years. b. c. Explain whether Option A or Option B is the better investment choice. SOLUTION: a. Use the compound interest formula. Sample answer: The equation that represents Option A c. During the first 22 years, Option B is the better choice because the total is greater is . than that of Option A. However, after about 22 The equation that represents Option B years, the balance of Option A exceeds that of Option B, so Option A is the better choice. is 41. MULTIPLE REPRESENTATIONSIn this problem, you will explore the rapid increase of an b. exponential function. A large sheet of paper is cut in The graph that shows the balances for each half, and one of the resulting pieces is placed on top investment option after t years: of the other. Then the pieces in the stack are cut in half and placed on top of each other. Suppose this procedure is repeated several times. a. CONCRETE Perform this activity and count the number of sheets in the stack after the first cut. How many pieces will there be after the second cut? How many pieces after the third cut? How many pieces after the fourth cut? b. TABULAR Record your results in a table. c. SYMBOLIC Use the pattern in the table to write an equation for the number of pieces in the stack after x cuts. d. ANALYTICAL The thickness of ordinary paper is about 0.003 inch. Write an equation for the thickness of the stack of paper after x cuts. e.ANALYTICAL How thick will the stack of c. During the first 22 years, Option B is the better paper be after 30 cuts? choice because the total is greater than that of Option A. However, after about 22 years, the SOLUTION: balance of Option A exceeds that of Option B, so a. Option A is the better choice. There will be 2, 4, 8, 16 pieces after the first, second, third and fourth cut respectively. b. ANSWER: a. b. c. The equation that represent the situation is d. Substitute 0.003 for a and 2 for b in the exponential function. e. Substitute 30 for x in the equation and simplify. Sample answer: c. During the first 22 years, Option B is the better choice because the total is greater than that of Option A. However, after about 22 years, the balance of Option A exceeds that of Option B, so Option A is the better choice. The thickness of the stack of paper after 30 cuts is about 3221225.47 in. 41. MULTIPLE REPRESENTATIONSIn this problem, you will explore the rapid increase of an exponential function. A large sheet of paper is cut in ANSWER: half, and one of the resulting pieces is placed on top a. 2, 4, 8, 16 b of the other. Then the pieces in the stack are cut in . half and placed on top of each other. Suppose this procedure is repeated several times. a. CONCRETE Perform this activity and count the number of sheets in the stack after the first cut. How many pieces will there be after the second cut? How many pieces after the third cut? How many pieces x after the fourth cut? c. y = 2 x d b. TABULAR . y = 0.003(2) Record your results in a table. e. about 3,221,225.47 in. c. SYMBOLIC Use the pattern in the table to write an equation for the number of pieces in the stack 42. WRITING IN MATHIn a problem about after x cuts. compound interest, describe what happens as the d. ANALYTICAL The thickness of ordinary paper compounding period becomes more frequent while is about 0.003 inch. Write an equation for the the principal and overall time remain the same. thickness of the stack of paper after x cuts. e.ANALYTICAL How thick will the stack of SOLUTION: paper be after 30 cuts? Sample answer: The more frequently interest is compounded, the higher the account balance SOLUTION: becomes. a. There will be 2, 4, 8, 16 pieces after the first, second, third and fourth cut respectively. ANSWER: b. Sample answer: The more frequently interest is compounded, the higher the account balance becomes. x − ERROR ANALYSIS 43. Beth and Liz are solving 6 3 > 36−x − 1. Is either of them correct? Explain your reasoning. c. The equation that represent the situation is d. Substitute 0.003 for a and 2 for b in the exponential function. e. Substitute 30 for x in the equation and simplify. The thickness of the stack of paper after 30 cuts is about 3221225.47 in. ANSWER: a. 2, 4, 8, 16 b . SOLUTION: Sample answer: Beth; Liz added the exponents x instead of multiplying them when taking the power of c. y = 2 x a power. d . y = 0.003(2) e. about 3,221,225.47 in. ANSWER: Sample answer: Beth; Liz added the exponents 42. WRITING IN MATHIn a problem about instead of multiplying them when taking the power of compound interest, describe what happens as the a power. compounding period becomes more frequent while the principal and overall time remain the same. 18 18 18 44. CHALLENGESolve for x: 16 + 16 + 16 + 18 18 x 16 + 16 = 4 . SOLUTION: Sample answer: The more frequently interest is compounded, the higher the account balance SOLUTION: becomes. ANSWER: Sample answer: The more frequently interest is compounded, the higher the account balance becomes. x − ERROR ANALYSIS 43. Beth and Liz are solving 6 3 > 36−x − 1. Is either of them correct? Explain your reasoning. ANSWER: 37.1610 45. OPEN ENDEDWhat would be a more beneficial change to a 5-year loan at 8% interest compounded monthly: reducing the term to 4 years or reducing the interest rate to 6.5%? SOLUTION: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the 6.5%. ANSWER: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the 6.5%. CCSS ARGUMENTS 46. Determine whether the following statements are sometimes, always, or never true. Explain your reasoning. a. x 20x 2 > −8 for all values of x. b. The graph of an exponential growth equation is increasing. c. The graph of an exponential decay equation is increasing. SOLUTION: Sample answer: Beth; Liz added the exponents SOLUTION: a. x 20x instead of multiplying them when taking the power of Always; 2 will always be positive, and −8 will always be negative. a power. b. Always; by definition the graph will always be ANSWER: increasing even if it is a small increase. Sample answer: Beth; Liz added the exponents c. Never; by definition the graph will always be instead of multiplying them when taking the power of decreasing even if it is a small decrease. a power. ANSWER: 18 18 18 x 20x 44. CHALLENGESolve for x: 16 + 16 + 16 + a . Always; 2 will always be positive, and 8 will 18 18 x − 16 + 16 = 4 . always be negative. b . Always; by definition the graph will always be SOLUTION: increasing even if it is a small increase. c. Never; by definition the graph will always be decreasing even if it is a small decrease. OPEN ENDEDWrite an exponential inequality with 47. a solution of x 2. ≤ SOLUTION: x 2 Sample answer: 4 4 ≤ ANSWER: x 2 ANSWER: Sample answer: 4 ≤ 4 37.1610 2x x + 1 2x + 2 4x + 1 PROOFShow that 27 · 81 = 3 · 9 . 48. 45. OPEN ENDEDWhat would be a more beneficial change to a 5-year loan at 8% interest compounded SOLUTION: monthly: reducing the term to 4 years or reducing the interest rate to 6.5%? SOLUTION: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the 6.5%. ANSWER: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the 6.5%. ANSWER: CCSS ARGUMENTS 46. Determine whether the following statements are sometimes, always, or never true. Explain your reasoning. a. x 20x 2 > −8 for all values of x. b. The graph of an exponential growth equation is increasing. c. The graph of an exponential decay equation is increasing. WRITING IN MATHIf you were given the initial 49. SOLUTION: and final amounts of a radioactive substance and the a. x 20x amount of time that passes, how would you Always; 2 will always be positive, and −8 will always be negative. determine the rate at which the amount was b. Always; by definition the graph will always be increasing or decreasing in order to write an increasing even if it is a small increase. equation? c. Never; by definition the graph will always be decreasing even if it is a small decrease. SOLUTION: Sample answer: Divide the final amount by the initial amount. If n is the number of time intervals that pass, ANSWER: take the nth root of the answer. a x 20x . Always; 2 will always be positive, and 8 will − always be negative. ANSWER: b . Always; by definition the graph will always be Sample answer: Divide the final amount by the initial increasing even if it is a small increase. amount. If n is the number of time intervals that pass, c. Never; by definition the graph will always be take the nth root of the answer. decreasing even if it is a small decrease. −4 = 50. 3 × 10 OPEN ENDEDWrite an exponential inequality with 47. A 30,000 a solution of x 2. − ≤ B 0.0003 C 120 − SOLUTION: x 2 D0.00003 Sample answer: 4 4 ≤ SOLUTION: ANSWER: x 2 Sample answer: 4 4 ≤ 2x x + 1 2x + 2 4x + 1 PROOFShow that 27 · 81 = 3 · 9 . 48. SOLUTION: B is the correct option. ANSWER: B 51. Which of the following could not be a solution to 5 − 3x < 3? − F2.5 G3 H 3.5 J 4 ANSWER: SOLUTION: Check the inequality by substituting 2.5 for x. So, F is the correct option. WRITING IN MATHIf you were given the initial 49. and final amounts of a radioactive substance and the ANSWER: F amount of time that passes, how would you determine the rate at which the amount was GRIDDED RESPONSEThe three angles of a increasing or decreasing in order to write an 52. equation? triangle are 3x, x + 10, and 2x − 40. Find the measure of the smallest angle in the triangle. SOLUTION: Sample answer: Divide the final amount by the initial SOLUTION: Sum of the three angles in a triangle is 180 . amount. If n is the number of time intervals that pass, º take the nth root of the answer. ANSWER: Sample answer: Divide the final amount by the initial amount. If n is the number of time intervals that pass, take the nth root of the answer. −4 = 50. 3 × 10 A 30,000 − B 0.0003 C 120 − D 0.00003 The measure of the smallest angle in the triangle is 30 . º SOLUTION: ANSWER: 30 SAT/ACT Which of the following is equivalent to 53. (x)(x)(x)(x) for all x? A x + 4 B is the correct option. B 4 x 2 ANSWER: C 2x B D 4x2 Which of the following could not be a solution to 5 4 51. − E 3x < 3? x − SOLUTION: F2.5 G3 H 3.5 J 4 E is the correct choice. SOLUTION: Check the inequality by substituting 2.5 for x. ANSWER: E Graph each function. x y = 2(3) 54. So, F is the correct option. SOLUTION: Make a table of values. Then plot the points and ANSWER: sketch the graph. F GRIDDED RESPONSEThe three angles of a 52. triangle are 3x, x + 10, and 2x − 40. Find the measure of the smallest angle in the triangle. SOLUTION: Sum of the three angles in a triangle is 180 . º The measure of the smallest angle in the triangle is 30 . º ANSWER: ANSWER: 30 SAT/ACT Which of the following is equivalent to 53. (x)(x)(x)(x) for all x? A x + 4 B 4x C 2x2 D 4x2 E 4 x x y = 5(2) 55. SOLUTION: SOLUTION: Make a table of values. Then plot the points and sketch the graph. E is the correct choice. ANSWER: E Graph each function. x y = 2(3) 54. SOLUTION: Make a table of values. Then plot the points and sketch the graph. ANSWER: ANSWER: 56. SOLUTION: Make a table of values. Then plot the points and sketch the graph. x y = 5(2) 55. SOLUTION: Make a table of values. Then plot the points and sketch the graph. ANSWER: ANSWER: Solve each equation. 57. SOLUTION: ANSWER: 4 56. SOLUTION: Make a table of values. Then plot the points and 58. sketch the graph. SOLUTION: ANSWER: 18 59. SOLUTION: ANSWER: ANSWER: 8.5 60. SOLUTION: Solve each equation. 57. The square root of x cannot be negative, so there is SOLUTION: no solution. ANSWER: no solution 61. SOLUTION: ANSWER: 4 58. SOLUTION: ANSWER: 5 62. SOLUTION: ANSWER: 18 59. SOLUTION: ANSWER: 20 − 63. ANSWER: 8.5 SOLUTION: 60. SOLUTION: ANSWER: 5 The square root of x cannot be negative, so there is no solution. 64. SOLUTION: ANSWER: no solution 61. SOLUTION: ANSWER: ANSWER: 5 65. 62. SOLUTION: SOLUTION: ANSWER: 1 − ANSWER: 20 − SALES A salesperson earns $10 an hour plus a 10% 66. commission on sales. Write a function to describe the salesperson’s income. If the salesperson wants to 63. earn $1000 in a 40-hour week, what should his sales be? SOLUTION: SOLUTION: Let I be the income of the salesperson and m be his sales. The function that represent the situation is . Substitute 1000 for I in the equation and solve for m. ANSWER: 5 ANSWER: I(m) = 400 + 0.1m; $6000 64. STATE FAIRA dairy makes three types of SOLUTION: 67. cheese cheddar, Monterey Jack, and Swiss and — — sells the cheese in three booths at the state fair. At the beginning of one day, the first booth received x pounds of each type of cheese. The second booth received y pounds of each type of cheese, and the third booth received z pounds of each type of cheese. By the end of the day, the dairy had sold 131 pounds of cheddar, 291 pounds of Monterey Jack, and 232 pounds of Swiss. The table below shows the percent of the cheese delivered in the morning that was sold at each booth. How many pounds of cheddar cheese ANSWER: did each booth receive in the morning? 65. SOLUTION: SOLUTION: The system of equations that represent the situation: ANSWER: Eliminate the variable x by using two pairs of 1 equations. − SALESA salesperson earns $10 an hour plus a 10% 66. Subtract (1) and (2). commission on sales. Write a function to describe the salesperson s income. If the salesperson wants to ’ earn $1000 in a 40-hour week, what should his sales be? SOLUTION: Let I be the income of the salesperson and m be his Multiply (2) by 3 and (3) by 4 and subtract both the sales. equations. The function that represent the situation is . Substitute 1000 for I in the equation and solve for m. Solve the system of two equations: ANSWER: I(m) = 400 + 0.1m; $6000 STATE FAIRA dairy makes three types of 67. cheese cheddar, Monterey Jack, and Swiss and — — sells the cheese in three booths at the state fair. At the beginning of one day, the first booth received x pounds of each type of cheese. The second booth received y pounds of each type of cheese, and the Substitute z = 100 in the equation third booth received z pounds of each type of cheese. By the end of the day, the dairy had sold 131 pounds of cheddar, 291 pounds of Monterey Jack, and 232 pounds of Swiss. The table below shows the percent of the cheese delivered in the morning that was sold at each booth. How many pounds of cheddar cheese did each booth receive in the morning? Substitute y = 150 and z = 100 in the (1) and solve for x. SOLUTION: The system of equations that represent the situation: Booth 1 has 190 lb; Booth 2 has 150 lb; Booth 3 has 100 lb. ANSWER: booth 1, 190 lb; booth 2, 150 lb; booth 3, 100 lb Find [g h](x) and [h g](x). Eliminate the variable x by using two pairs of ◦ ◦ 68. h(x) = 2x − 1 equations. g(x) = 3x + 4 Subtract (1) and (2). SOLUTION: Multiply (2) by 3 and (3) by 4 and subtract both the equations. ANSWER: 6x + 1; 6x + 7 h(x) = x2 + 2 69. Solve the system of two equations: g(x) = x − 3 SOLUTION: Substitute z = 100 in the equation ANSWER: x2 1; x2 6x + 11 − − h(x) = x2 + 1 70. g(x) = 2x + 1 − Substitute y = 150 and z = 100 in the (1) and solve SOLUTION: for x. Booth 1 has 190 lb; Booth 2 has 150 lb; Booth 3 has ANSWER: 2x2 1; 4x2 4x + 2 100 lb. − − − h(x) = 5x 71. − ANSWER: booth 1, 190 lb; booth 2, 150 lb; booth 3, 100 lb g(x) = 3x − 5 Find [g h](x) and [h g](x). SOLUTION: ◦ ◦ 68. h(x) = 2x − 1 g(x) = 3x + 4 SOLUTION: ANSWER: 15x 5; 15x + 25 − − − h(x) = x3 72. g(x) = x − 2 SOLUTION: ANSWER: 6x + 1; 6x + 7 h(x) = x2 + 2 69. g(x) = x − 3 ANSWER: 3 3 2 SOLUTION: x x 6x + 12x 8 −2; − − 73. h(x) = x + 4 g(x) = | x | SOLUTION: ANSWER: 2 2 ANSWER: x 1; x 6x + 11 − − | x + 4 | ; | x | + 4 h(x) = x2 + 1 70. g(x) = 2x + 1 − SOLUTION: ANSWER: 2x2 1; 4x2 4x + 2 − − − h(x) = 5x 71. − g(x) = 3x − 5 SOLUTION: ANSWER: 15x 5; 15x + 25 − − − h(x) = x3 72. g(x) = x − 2 SOLUTION: ANSWER: 3 3 2 x x 6x + 12x 8 −2; − − 73. h(x) = x + 4 g(x) = | x | SOLUTION: ANSWER: | x + 4 | ; | x | + 4 Solve each equation. 5x 2x − 4 1. 3 = 27 SOLUTION: Use the Property of Equality for Exponential Functions. ANSWER: 12 2y − 3 y + 1 Solve each equation. 2. 16 = 4 5x 2x − 4 1. 3 = 27 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Use the Property of Equality for Exponential Functions. Functions. ANSWER: 12 ANSWER: 2y − 3 y + 1 2. 16 = 4 SOLUTION: 6x x − 2 3. 2 = 32 SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: ANSWER: −10 x + 5 8x − 6 4. 49 = 7 6x x − 2 3. 2 = 32 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Use the Property of Equality for Exponential Functions. Functions. ANSWER: −10 ANSWER: x + 5 8x − 6 4. 49 = 7 SOLUTION: SCIENCE 5. Mitosis is a process in which one cell divides into two. The Escherichia coli is one of the fastest growing bacteria. It can reproduce itself in 15 minutes. a. Write an exponential function to represent the number of cells c after t minutes. Use the Property of Equality for Exponential b. If you begin with one Escherichia coli cell, how Functions. many cells will there be in one hour? SOLUTION: a. The exponential function that represent the number of cells after t minutes is . b. Substitute 1 for t in the function and solve for c. ANSWER: ANSWER: SCIENCE 5. Mitosis is a process in which one cell divides into two. The Escherichia coli is one of the a. fastest growing bacteria. It can reproduce itself in 15 b. 16 cells minutes. a. Write an exponential function to represent the 6. A certificate of deposit (CD) pays 2.25% annual number of cells c after t minutes. interest compounded biweekly. If you deposit $500 b. If you begin with one Escherichia coli cell, how into this CD, what will the balance be after 6 years? many cells will there be in one hour? SOLUTION: SOLUTION: Use the compound interest formula. a. Substitute $500 for P, 0.0225 for r, 26 for n and 6 for The exponential function that represent the number t and simplify. of cells after t minutes is . b. Substitute 1 for t in the function and solve for c. ANSWER: a. ANSWER: b. 16 cells $572.23 6. A certificate of deposit (CD) pays 2.25% annual Solve each inequality. interest compounded biweekly. If you deposit $500 2x + 6 2x – 4 into this CD, what will the balance be after 6 years? 7. 4 ≤64 SOLUTION: SOLUTION: Use the compound interest formula. Substitute $500 for P, 0.0225 for r, 26 for n and 6 for t and simplify. Use the Property of Inequality for Exponential Functions. ANSWER: $572.23 ANSWER: x ≥ 4.5 Solve each inequality. 2x + 6 2x – 4 7. 4 ≤64 8. SOLUTION: SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: ANSWER: x ≥ 4.5 Solve each equation. 8. 4x + 2 9. 8 = 64 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: 0 ANSWER: x − 6 10. 5 = 125 Solve each equation. 4x + 2 SOLUTION: 9. 8 = 64 SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: 9 ANSWER: a + 2 3a + 1 0 11. 81 = 3 SOLUTION: x − 6 10. 5 = 125 SOLUTION: Use the Property of Equality for Exponential Use the Property of Equality for Exponential Functions. Functions. ANSWER: −7 ANSWER: 9 b + 2 2 − 2b 12. 256 = 4 a + 2 3a + 1 11. 81 = 3 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Use the Property of Equality for Exponential Functions. Functions. ANSWER: ANSWER: −1 −7 b + 2 2 − 2b 3c + 1 3c − 1 12. 256 = 4 13. 9 = 27 SOLUTION: SOLUTION: Use the Property of Equality for Exponential Use the Property of Equality for Exponential Functions. Functions. ANSWER: −1 ANSWER: 3c + 1 3c − 1 13. 9 = 27 SOLUTION: 2y + 4 y + 1 14. 8 = 16 SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: 7-2 Solving Exponential Equations and Inequalities ANSWER: −4 2y + 4 y + 1 14. 8 = 16 15. CCSS MODELINGIn 2009, My-Lien received $10,000 from her grandmother. Her parents invested SOLUTION: all of the money, and by 2021, the amount will have grown to $16,960. a. Write an exponential function that could be used to model the money y. Write the function in terms of x, the number of years since 2009. b. Assume that the amount of money continues to Use the Property of Equality for Exponential grow at the same rate. What would be the balance in Functions. the account in 2031? SOLUTION: a. Substitute 16780 for y 10000 for a and 12 for x in the exponential function and simplify. ANSWER: −4 15. CCSS MODELINGIn 2009, My-Lien received $10,000 from her grandmother. Her parents invested all of the money, and by 2021, the amount will have grown to $16,960. The exponential function that models the situation a. Write an exponential function that could be used to model the money y. Write the function in terms of x, is . the number of years since 2009. b. Assume that the amount of money continues to b. grow at the same rate. What would be the balance in Substitute 22 for x in the modeled function and solve the account in 2031? for y. SOLUTION: a. Substitute 16780 for y 10000 for a and 12 for x in the exponential function and simplify. ANSWER: x a . y = 10,000(1.045) b . about $26,336.52 Write an exponential function for the graph that passes through the given points. 16. (0, 6.4) and (3, 100) The exponential function that models the situation SOLUTION: is . Substitute 100 for y and 6.4 for a and 3 for x into an exponential function and determine the value of b. b. Substitute 22 for x in the modeled function and solve for y. eSolutions Manual - Powered by Cognero Page4 ANSWER: An exponential function that passes through the given x a . y = 10,000(1.045) points is . b . about $26,336.52 Write an exponential function for the graph that ANSWER: x passes through the given points. y = 6.4(2.5) 16. (0, 6.4) and (3, 100) SOLUTION: 17. (0, 256) and (4, 81) Substitute 100 for y and 6.4 for a and 3 for x into an exponential function and determine the value of b. SOLUTION: Substitute 81 for y and 256 for a and 4 for x into an exponential function and determine the value of b. An exponential function that passes through the given points is . An exponential function that passes through the given points is . ANSWER: x y = 6.4(2.5) ANSWER: x y = 256(0.75) 17. (0, 256) and (4, 81) 18. (0, 128) and (5, 371,293) SOLUTION: Substitute 81 for y and 256 for a and 4 for x into an SOLUTION: exponential function and determine the value of b. Substitute 371293 for y and 128 for a and 5 for x into an exponential function and determine the value of b. An exponential function that passes through the given points is . An exponential function that passes through the given points is . ANSWER: x y = 256(0.75) ANSWER: x y = 128(4.926) 18. (0, 128) and (5, 371,293) 19. (0, 144), and (4, 21,609) SOLUTION: Substitute 371293 for y and 128 for a and 5 for x into SOLUTION: an exponential function and determine the value of b. Substitute 21609 for y and 144 for a and 4 for x into an exponential function and determine the value of b. An exponential function that passes through the given points is . An exponential function that passes through the given points is . ANSWER: x y = 128(4.926) ANSWER: x y = 144(3.5) 19. (0, 144), and (4, 21,609) 20. Find the balance of an account after 7 years if $700 SOLUTION: is deposited into an account paying 4.3% interest Substitute 21609 for y and 144 for a and 4 for x into compounded monthly. an exponential function and determine the value of b. SOLUTION: Use the compound interest formula. Substitute $700 for P, 0.043 for r, 12 for n and 7 for t and simplify. An exponential function that passes through the given points is . ANSWER: ANSWER: x y = 144(3.5) $945.34 20. Find the balance of an account after 7 years if $700 21. Determine how much is in a retirement account after is deposited into an account paying 4.3% interest 20 years if $5000 was invested at 6.05% interest compounded monthly. compounded weekly. SOLUTION: SOLUTION: Use the compound interest formula. Use the compound interest formula. Substitute $700 for P, 0.043 for r, 12 for n and 7 for t Substitute $5000 for P, 0.0605 for r, 52 for n and 20 and simplify. for t and simplify. ANSWER: ANSWER: $945.34 $16,755.63 21. Determine how much is in a retirement account after 22. A savings account offers 0.7% interest compounded 20 years if $5000 was invested at 6.05% interest bimonthly. If $110 is deposited in this account, what compounded weekly. will the balance be after 15 years? SOLUTION: SOLUTION: Use the compound interest formula. Use the compound interest formula. Substitute $5000 for P, 0.0605 for r, 52 for n and 20 Substitute $110 for P, 0.007 for r, 6 for n and 15 for t for t and simplify. and simplify. ANSWER: ANSWER: $16,755.63 $122.17 22. A savings account offers 0.7% interest compounded 23. A college savings account pays 13.2% annual bimonthly. If $110 is deposited in this account, what interest compounded semiannually. What is the will the balance be after 15 years? balance of an account after 12 years if $21,000 was initially deposited? SOLUTION: Use the compound interest formula. SOLUTION: Substitute $110 for P, 0.007 for r, 6 for n and 15 for t Use the compound interest formula. and simplify. Substitute $21,000 for P, 0.132 for r, 2 for n and 12 for t and simplify. ANSWER: $122.17 ANSWER: 23. A college savings account pays 13.2% annual $97,362.61 interest compounded semiannually. What is the Solve each inequality. balance of an account after 12 years if $21,000 was initially deposited? 24. SOLUTION: SOLUTION: Use the compound interest formula. Substitute $21,000 for P, 0.132 for r, 2 for n and 12 for t and simplify. Use the Property of Inequality for Exponential Functions. ANSWER: ANSWER: $97,362.61 25. Solve each inequality. SOLUTION: 24. SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: ANSWER: 25. 26. SOLUTION: SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: 26. ANSWER: SOLUTION: 27. SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: ANSWER: 27. SOLUTION: 28. SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: 28. ANSWER: SOLUTION: 29. SOLUTION: Use the Property of Inequality for Exponential Functions. Use the Property of Inequality for Exponential Functions. ANSWER: 29. ANSWER: SOLUTION: 30. SCIENCEA mug of hot chocolate is 90°C at time t = 0. It is surrounded by air at a constant temperature of 20°C. If stirred steadily, its temperature in Celsius −t after t minutes will be y(t) = 20 + 70(1.071) . a. Find the temperature of the hot chocolate after 15 minutes. Use the Property of Inequality for Exponential b. Find the temperature of the hot chocolate after 30 Functions. minutes. c. The optimum drinking temperature is 60°C. Will the mug of hot chocolate be at or below this temperature after 10 minutes? SOLUTION: a. Substitute 15 for t in the equation and simplify. ANSWER: b. 30. SCIENCEA mug of hot chocolate is 90°C at time t Substitute 30 for t in the equation and simplify. = 0. It is surrounded by air at a constant temperature of 20°C. If stirred steadily, its temperature in Celsius −t after t minutes will be y(t) = 20 + 70(1.071) . a. Find the temperature of the hot chocolate after 15 c. minutes. Substitute 10 for t in the equation and simplify. b. Find the temperature of the hot chocolate after 30 minutes. c. So, temperature of the hot chocolate will be below The optimum drinking temperature is 60°C. Will the mug of hot chocolate be at or below this 60°C after 10 minutes. temperature after 10 minutes? ANSWER: SOLUTION: a a. . 45.02° C b Substitute 15 for t in the equation and simplify. . 28.94° C c. below 31. ANIMALSStudies show that an animal will defend b. a territory, with area in square yards, that is directly Substitute 30 for t in the equation and simplify. proportional to the 1.31 power of the animal’s weight in pounds. a. If a 45-pound beaver will defend 170 square yards, write an equation for the area a defended by a beaver weighing w pounds. c. b. Scientists believe that thousands of years ago, the Substitute 10 for t in the equation and simplify. beaver’s ancestors were 11 feet long and weighed 430 pounds. Use your equation to determine the area defended by these animals. So, temperature of the hot chocolate will be below SOLUTION: 60°C after 10 minutes. a. ANSWER: Substitute 170 for y, 45 for b, and 1.31 for x in the a exponential function. . 45.02° C b . 28.94° C c. below 31. ANIMALSStudies show that an animal will defend a territory, with area in square yards, that is directly proportional to the 1.31 power of the animal’s weight in pounds. The equation for the area a defended by a beaver a. If a 45-pound beaver will defend 170 square yards, weighting w pounds is write an equation for the area a defended by a b. beaver weighing w pounds. Substitute 430 for w in the equation and solve for y. b. Scientists believe that thousands of years ago, the beaver’s ancestors were 11 feet long and weighed 430 pounds. Use your equation to determine the area defended by these animals. SOLUTION: a. ANSWER: a 1.31 Substitute 170 for y, 45 for b, and 1.31 for x in the . a = 1.16w exponential function. b 2 . about 3268 yd Solve each equation. 32. SOLUTION: The equation for the area a defended by a beaver weighting w pounds is b. Substitute 430 for w in the equation and solve for y. Use the Property of Equality for Exponential Functions. ANSWER: a 1.31 . a = 1.16w b 2 . about 3268 yd Solve each equation. ANSWER: 32. SOLUTION: 33. SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: ANSWER: 33. SOLUTION: 34. SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: ANSWER: −6 34. 35. SOLUTION: SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: −6 35. ANSWER: SOLUTION: 36. SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential ANSWER: Functions. 36. SOLUTION: ANSWER: 37. SOLUTION: Use the Property of Equality for Exponential Functions. Use the Property of Equality for Exponential Functions. ANSWER: ANSWER: 1 37. 38. CCSS MODELINGIn 1950, the world population SOLUTION: was about 2.556 billion. By 1980, it had increased to about 4.458 billion. a. x Write an exponential function of the form y = ab that could be used to model the world population y in billions for 1950 to 1980. Write the equation in terms of x, the number of years since 1950. (Round the value of b to the nearest ten-thousandth.) Use the Property of Equality for Exponential b. Suppose the population continued to grow at that Functions. rate. Estimate the population in 2000. c. In 2000, the population of the world was about 6.08 billion. Compare your estimate to the actual population. d. Use the equation you wrote in Part a to estimate the world population in the year 2020. How accurate do you think the estimate is? Explain your reasoning. ANSWER: 1 SOLUTION: a. 38. CCSS MODELINGIn 1950, the world population Substitute 4.458 for y, 2.556 for a, and 30 for x in the was about 2.556 billion. By 1980, it had increased to exponential function and solve for b. about 4.458 billion. a. x Write an exponential function of the form y = ab that could be used to model the world population y in billions for 1950 to 1980. Write the equation in terms of x, the number of years since 1950. (Round the value of b to the nearest ten-thousandth.) b. Suppose the population continued to grow at that The exponential function that model the situation is rate. Estimate the population in 2000. . c. In 2000, the population of the world was about b. 6.08 billion. Compare your estimate to the actual Substitute 50 for x in the equation and simplify. population. d. Use the equation you wrote in Part a to estimate the world population in the year 2020. How accurate do you think the estimate is? Explain your reasoning. SOLUTION: a. c. The prediction was about 375 million greater than Substitute 4.458 for y, 2.556 for a, and 30 for x in the the actual population. exponential function and solve for b. d. Substitute 70 for x in the equation and simplify. The exponential function that model the situation is Because the prediction for 2000 was greater than the . actual population, this prediction for 2020 is probably even higher than the actual population will be at the b. time. Substitute 50 for x in the equation and simplify. ANSWER: x a . y = 2.556(1.0187) b . 6.455 billion c. The prediction was about 375 million greater than the actual. c. The prediction was about 375 million greater than d the actual population. . About 9.3498 billion; because the prediction for d. 2000 was greater than the actual population, this Substitute 70 for x in the equation and simplify. prediction is probably even higher than the actual population will be at the time. 39. TREES The diameter of the base of a tree trunk in centimeters varies directly with the power of its height in meters. Because the prediction for 2000 was greater than the a. A young sequoia tree is 6 meters tall, and the actual population, this prediction for 2020 is probably diameter of its base is 19.1 centimeters. Use this even higher than the actual population will be at the information to write an equation for the diameter d of time. the base of a sequoia tree if its height is h meters high ANSWER: b. The General Sherman Tree in Sequoia National x a . y = 2.556(1.0187) Park, California, is approximately 84 meters tall. b . 6.455 billion Find the diameter of the General Sherman Tree at its c. The prediction was about 375 million greater than the actual. base. d . About 9.3498 billion; because the prediction for 2000 was greater than the actual population, this SOLUTION: prediction is probably even higher than the actual a. population will be at the time. The equation that represent the situation is 39. TREES The diameter of the base of a tree trunk in . centimeters varies directly with the power of its b. Substitute 84 for h in the equation and solve for d. height in meters. a. A young sequoia tree is 6 meters tall, and the diameter of its base is 19.1 centimeters. Use this information to write an equation for the diameter d of the base of a sequoia tree if its height is h meters The diameter of the General Sherman Tree at its high b. The General Sherman Tree in Sequoia National base is about 1001 cm. Park, California, is approximately 84 meters tall. Find the diameter of the General Sherman Tree at its ANSWER: base. a. b . about 1001 cm SOLUTION: a. 40. FINANCIAL LITERACYMrs. Jackson has two The equation that represent the situation is different retirement investment plans from which to choose. . a. Write equations for Option A and Option B given b. the minimum deposits. Substitute 84 for h in the equation and solve for d. b. Draw a graph to show the balances for each investment option after t years. c. Explain whether Option A or Option B is the better investment choice. The diameter of the General Sherman Tree at its base is about 1001 cm. ANSWER: a. b . about 1001 cm 40. FINANCIAL LITERACYMrs. Jackson has two different retirement investment plans from which to SOLUTION: choose. a. a. Write equations for Option A and Option B given Use the compound interest formula. the minimum deposits. The equation that represents Option A b. Draw a graph to show the balances for each is . investment option after t years. The equation that represents Option B c. Explain whether Option A or Option B is the better investment choice. is b. The graph that shows the balances for each investment option after t years: SOLUTION: a. Use the compound interest formula. The equation that represents Option A is . The equation that represents Option B is c. b. During the first 22 years, Option B is the better The graph that shows the balances for each choice because the total is greater than that of investment option after t years: Option A. However, after about 22 years, the balance of Option A exceeds that of Option B, so Option A is the better choice. ANSWER: a. b. c. During the first 22 years, Option B is the better choice because the total is greater than that of Option A. However, after about 22 years, the balance of Option A exceeds that of Option B, so Option A is the better choice. Sample answer: c. During the first 22 years, Option ANSWER: B is the better choice because the total is greater a. than that of Option A. However, after about 22 b. years, the balance of Option A exceeds that of Option B, so Option A is the better choice. 41. MULTIPLE REPRESENTATIONSIn this problem, you will explore the rapid increase of an exponential function. A large sheet of paper is cut in half, and one of the resulting pieces is placed on top of the other. Then the pieces in the stack are cut in half and placed on top of each other. Suppose this procedure is repeated several times. a. CONCRETE Perform this activity and count the number of sheets in the stack after the first cut. How many pieces will there be after the second cut? How many pieces after the third cut? How many pieces after the fourth cut? b. TABULAR Record your results in a table. Sample answer: c. c. SYMBOLIC During the first 22 years, Option Use the pattern in the table to write B is the better choice because the total is greater an equation for the number of pieces in the stack than that of Option A. However, after about 22 after x cuts. years, the balance of Option A exceeds that of d. ANALYTICAL Option B, so Option A is the better choice. The thickness of ordinary paper is about 0.003 inch. Write an equation for the thickness of the stack of paper after x cuts. 41. MULTIPLE REPRESENTATIONSIn this e.ANALYTICAL problem, you will explore the rapid increase of an How thick will the stack of exponential function. A large sheet of paper is cut in paper be after 30 cuts? half, and one of the resulting pieces is placed on top SOLUTION: of the other. Then the pieces in the stack are cut in a. half and placed on top of each other. Suppose this There will be 2, 4, 8, 16 pieces after the first, second, procedure is repeated several times. third and fourth cut respectively. a. CONCRETE b. Perform this activity and count the number of sheets in the stack after the first cut. How many pieces will there be after the second cut? How many pieces after the third cut? How many pieces after the fourth cut? b. TABULAR Record your results in a table. c. SYMBOLIC Use the pattern in the table to write an equation for the number of pieces in the stack c. after x cuts. The equation that represent the situation is d. ANALYTICAL The thickness of ordinary paper d. is about 0.003 inch. Write an equation for the Substitute 0.003 for a and 2 for b in the exponential thickness of the stack of paper after x cuts. function. e.ANALYTICAL How thick will the stack of paper be after 30 cuts? e. SOLUTION: a. Substitute 30 for x in the equation and There will be 2, 4, 8, 16 pieces after the first, second, simplify. third and fourth cut respectively. b. The thickness of the stack of paper after 30 cuts is about 3221225.47 in. ANSWER: c. a. 2, 4, 8, 16 The equation that represent the situation is b d. . Substitute 0.003 for a and 2 for b in the exponential function. e. Substitute 30 for x in the equation and x c. y = 2 simplify. x d . y = 0.003(2) e. about 3,221,225.47 in. 42. WRITING IN MATHIn a problem about compound interest, describe what happens as the The thickness of the stack of paper after 30 cuts is compounding period becomes more frequent while about 3221225.47 in. the principal and overall time remain the same. SOLUTION: ANSWER: Sample answer: The more frequently interest is a. 2, 4, 8, 16 compounded, the higher the account balance b . becomes. ANSWER: Sample answer: The more frequently interest is compounded, the higher the account balance becomes. x − x ERROR ANALYSIS c. y = 2 43. Beth and Liz are solving 6 x 3 −x − 1 d > 36 . Is either of them correct? Explain your . y = 0.003(2) reasoning. e. about 3,221,225.47 in. 42. WRITING IN MATHIn a problem about compound interest, describe what happens as the compounding period becomes more frequent while the principal and overall time remain the same. SOLUTION: Sample answer: The more frequently interest is compounded, the higher the account balance becomes. ANSWER: Sample answer: The more frequently interest is compounded, the higher the account balance becomes. x − ERROR ANALYSIS 43. Beth and Liz are solving 6 3 > 36−x − 1. Is either of them correct? Explain your reasoning. SOLUTION: Sample answer: Beth; Liz added the exponents instead of multiplying them when taking the power of a power. ANSWER: Sample answer: Beth; Liz added the exponents instead of multiplying them when taking the power of a power. 18 18 18 44. CHALLENGESolve for x: 16 + 16 + 16 + 18 18 x 16 + 16 = 4 . SOLUTION: SOLUTION: Sample answer: Beth; Liz added the exponents instead of multiplying them when taking the power of a power. ANSWER: Sample answer: Beth; Liz added the exponents ANSWER: instead of multiplying them when taking the power of 37.1610 a power. 45. OPEN ENDEDWhat would be a more beneficial 18 18 18 change to a 5-year loan at 8% interest compounded 44. CHALLENGESolve for x: 16 + 16 + 16 + monthly: reducing the term to 4 years or reducing the 18 18 x 16 + 16 = 4 . interest rate to 6.5%? SOLUTION: SOLUTION: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the 6.5%. ANSWER: Reducing the term will be more beneficial. The multiplier is 1.3756 for the 4-year and 1.3828 for the 6.5%. CCSS ARGUMENTS 46. Determine whether the following statements are sometimes, always, or ANSWER: never true. Explain your reasoning. 37.1610 a. x 20x 2 > −8 for all values of x. b. The graph of an exponential growth equation is 45. OPEN ENDEDWhat would be a more beneficial increasing. change to a 5-year loan at 8% interest compounded monthly: reducing the term to 4 years or reducing the c. The graph of an exponential decay equation is interest rate to 6.5%? increasing. SOLUTION: SOLUTION: Reducing the term will be more beneficial. The a. x 20x multiplier is 1.3756 for the 4-year and 1.3828 for the Always; 2 will always be positive, and −8 will always be negative. 6.5%. b. Always; by definition the graph will always be increasing even if it is a small increase. ANSWER: Reducing the term will be more beneficial. The c. Never; by definition the graph will always be multiplier is 1.3756 for the 4-year and 1.3828 for the decreasing even if it is a small decrease. 6.5%. ANSWER: a x 20x . Always; 2 will always be positive, and 8 will − CCSS ARGUMENTS 46. Determine whether the always be negative. following statements are sometimes, always, or b never true. Explain your reasoning. . Always; by definition the graph will always be a. x 20x increasing even if it is a small increase. 2 > −8 for all values of x. c. Never; by definition the graph will always be b. The graph of an exponential growth equation is decreasing even if it is a small decrease. increasing. c. The graph of an exponential decay equation is OPEN ENDEDWrite an exponential inequality with increasing. 47. a solution of x 2. ≤ SOLUTION: x 20x SOLUTION: a. Always; 2 will always be positive, and −8 will x 2 Sample answer: 4 4 always be negative. ≤ b. Always; by definition the graph will always be increasing even if it is a small increase. ANSWER: x 2 Sample answer: 4 4 ≤ c. Never; by definition the graph will always be decreasing even if it is a small decrease. 2x x + 1 2x + 2 4x + 1 PROOFShow that 27 · 81 = 3 · 9 . 48. ANSWER: x 20x SOLUTION: a . Always; 2 will always be positive, and 8 will − always be negative. b . Always; by definition the graph will always be increasing even if it is a small increase. c. Never; by definition the graph will always be decreasing even if it is a small decrease. OPEN ENDEDWrite an exponential inequality with 47. a solution of x 2. ≤ SOLUTION: x 2 Sample answer: 4 4 ≤ ANSWER: ANSWER: x 2 Sample answer: 4 4 ≤ 2x x + 1 2x + 2 4x + 1 PROOFShow that 27 · 81 = 3 · 9 . 48. SOLUTION: WRITING IN MATHIf you were given the initial 49. and final amounts of a radioactive substance and the amount of time that passes, how would you determine the rate at which the amount was increasing or decreasing in order to write an equation? SOLUTION: Sample answer: Divide the final amount by the initial amount. If n is the number of time intervals that pass, ANSWER: take the nth root of the answer. ANSWER: Sample answer: Divide the final amount by the initial amount. If n is the number of time intervals that pass, take the nth root of the answer. −4 = 50. 3 × 10 A 30,000 − B 0.0003 WRITING IN MATHIf you were given the initial 49. C 120 and final amounts of a radioactive substance and the − amount of time that passes, how would you D 0.00003 determine the rate at which the amount was increasing or decreasing in order to write an SOLUTION: equation? SOLUTION: Sample answer: Divide the final amount by the initial amount. If n is the number of time intervals that pass, take the nth root of the answer. ANSWER: B is the correct option. Sample answer: Divide the final amount by the initial amount. If n is the number of time intervals that pass, ANSWER: B take the nth root of the answer. −4 = 51. Which of the following could not be a solution to 5 − 50. 3 × 10 3x < 3? A 30,000 − − B 0.0003 F2.5 C 120 G3 − H 3.5 D 0.00003 J 4 SOLUTION: SOLUTION: Check the inequality by substituting 2.5 for x. So, F is the correct option. B is the correct option. ANSWER: ANSWER: F B GRIDDED RESPONSEThe three angles of a Which of the following could not be a solution to 5 52. 51. − triangle are 3x, x + 10, and 2x 40. Find the measure 3x < 3? − − of the smallest angle in the triangle. F2.5 G3 SOLUTION: H3.5 Sum of the three angles in a triangle is 180 . º J 4 SOLUTION: Check the inequality by substituting 2.5 for x. So, F is the correct option. ANSWER: F The measure of the smallest angle in the triangle is 30 . º GRIDDED RESPONSEThe three angles of a 52. triangle are 3x, x + 10, and 2x − 40. Find the measure of the smallest angle in the triangle. ANSWER: 30 SOLUTION: Sum of the three angles in a triangle is 180 . SAT/ACT Which of the following is equivalent to º 53. (x)(x)(x)(x) for all x? A x + 4 B 4x C 2x2 D 4x2 E 4 x SOLUTION: The measure of the smallest angle in the triangle is 30 . º E is the correct choice. ANSWER: 30 ANSWER: E SAT/ACT Which of the following is equivalent to 53. Graph each function. (x)(x)(x)(x) for all x? x y = 2(3) 54. A x + 4 SOLUTION: B 4x Make a table of values. Then plot the points and C 2x2 sketch the graph. D 4x2 E 4 x SOLUTION: E is the correct choice. ANSWER: E Graph each function. x y = 2(3) 54. SOLUTION: Make a table of values. Then plot the points and sketch the graph. ANSWER: x y = 5(2) 55. SOLUTION: Make a table of values. Then plot the points and sketch the graph. ANSWER: x y = 5(2) 55. SOLUTION: Make a table of values. Then plot the points and sketch the graph. ANSWER: 56. SOLUTION: Make a table of values. Then plot the points and sketch the graph. ANSWER: 56. SOLUTION: Make a table of values. Then plot the points and sketch the graph. ANSWER: Solve each equation. 57. SOLUTION: ANSWER: ANSWER: 4 58. SOLUTION: Solve each equation. 57. SOLUTION: ANSWER: 18 59. ANSWER: 4 SOLUTION: 58. SOLUTION: ANSWER: 8.5 60. SOLUTION: ANSWER: 18 59. SOLUTION: The square root of x cannot be negative, so there is no solution. ANSWER: no solution ANSWER: 8.5 61. SOLUTION: 60. SOLUTION: ANSWER: 5 The square root of x cannot be negative, so there is no solution. 62. ANSWER: SOLUTION: no solution 61. SOLUTION: ANSWER: 20 − ANSWER: 63. 5 SOLUTION: 62. SOLUTION: ANSWER: 5 ANSWER: 64. 20 − SOLUTION: 63. SOLUTION: ANSWER: ANSWER: 5 65. 64. SOLUTION: SOLUTION: ANSWER: 1 − ANSWER: SALES A salesperson earns $10 an hour plus a 10% 66. commission on sales. Write a function to describe the salesperson’s income. If the salesperson wants to earn $1000 in a 40-hour week, what should his sales be? 65. SOLUTION: SOLUTION: Let I be the income of the salesperson and m be his sales. The function that represent the situation is . Substitute 1000 for I in the equation and solve for m. ANSWER: 1 ANSWER: − I(m) = 400 + 0.1m; $6000 SALES A salesperson earns $10 an hour plus a 10% 66. STATE FAIRA dairy makes three types of commission on sales. Write a function to describe the 67. cheese cheddar, Monterey Jack, and Swiss and salesperson s income. If the salesperson wants to — — ’ sells the cheese in three booths at the state fair. At earn $1000 in a 40-hour week, what should his sales the beginning of one day, the first booth received x be? pounds of each type of cheese. The second booth received y pounds of each type of cheese, and the SOLUTION: third booth received z pounds of each type of cheese. Let I be the income of the salesperson and m be his By the end of the day, the dairy had sold 131 pounds sales. of cheddar, 291 pounds of Monterey Jack, and 232 The function that represent the situation is pounds of Swiss. The table below shows the percent . of the cheese delivered in the morning that was sold Substitute 1000 for I in the equation and solve for m. at each booth. How many pounds of cheddar cheese did each booth receive in the morning? ANSWER: I(m) = 400 + 0.1m; $6000 STATE FAIRA dairy makes three types of 67. cheese cheddar, Monterey Jack, and Swiss and SOLUTION: — — The system of equations that represent the situation: sells the cheese in three booths at the state fair. At the beginning of one day, the first booth received x pounds of each type of cheese. The second booth received y pounds of each type of cheese, and the third booth received z pounds of each type of cheese. By the end of the day, the dairy had sold 131 pounds of cheddar, 291 pounds of Monterey Jack, and 232 pounds of Swiss. The table below shows the percent of the cheese delivered in the morning that was sold Eliminate the variable x by using two pairs of equations. at each booth. How many pounds of cheddar cheese did each booth receive in the morning? Subtract (1) and (2). Multiply (2) by 3 and (3) by 4 and subtract both the SOLUTION: equations. The system of equations that represent the situation: Solve the system of two equations: Eliminate the variable x by using two pairs of equations. Subtract (1) and (2). Substitute z = 100 in the equation Multiply (2) by 3 and (3) by 4 and subtract both the equations. Substitute y = 150 and z = 100 in the (1) and solve for x. Solve the system of two equations: Booth 1 has 190 lb; Booth 2 has 150 lb; Booth 3 has 100 lb. Substitute z = 100 in the equation ANSWER: booth 1, 190 lb; booth 2, 150 lb; booth 3, 100 lb Find [g h](x) and [h g](x). ◦ ◦ 68. h(x) = 2x − 1 g(x) = 3x + 4 Substitute y = 150 and z = 100 in the (1) and solve SOLUTION: for x. Booth 1 has 190 lb; Booth 2 has 150 lb; Booth 3 has ANSWER: 100 lb. 6x + 1; 6x + 7 ANSWER: 2 booth 1, 190 lb; booth 2, 150 lb; booth 3, 100 lb 69. h(x) = x + 2 g(x) = x − 3 Find [g h](x) and [h g](x). ◦ ◦ h(x) = 2x 1 SOLUTION: 68. − g(x) = 3x + 4 SOLUTION: ANSWER: x2 1; x2 6x + 11 − − 2 ANSWER: 70. h(x) = x + 1 g(x) = 2x + 1 6x + 1; 6x + 7 − SOLUTION: h(x) = x2 + 2 69. g(x) = x − 3 SOLUTION: ANSWER: 2x2 1; 4x2 4x + 2 − − − h(x) = 5x 71. − ANSWER: 2 2 g(x) = 3x − 5 x 1; x 6x + 11 − − SOLUTION: h(x) = x2 + 1 70. g(x) = 2x + 1 − SOLUTION: ANSWER: 15x 5; 15x + 25 − − − h(x) = x3 72. g(x) = x − 2 SOLUTION: ANSWER: 2x2 1; 4x2 4x + 2 − − − h(x) = 5x 71. − g(x) = 3x − 5 SOLUTION: ANSWER: 3 3 2 x x 6x + 12x 8 −2; − − 73. h(x) = x + 4 g(x) = | x | SOLUTION: ANSWER: 15x 5; 15x + 25 − − − h(x) = x3 72. ANSWER: g(x) = x − 2 | x + 4 | ; | x | + 4 SOLUTION: ANSWER: 3 3 2 x x 6x + 12x 8 −2; − − 73. h(x) = x + 4 g(x) = | x | SOLUTION: ANSWER: | x + 4 | ; | x | + 4
no reviews yet
Please Login to review.