182x Filetype PPT File size 0.63 MB Source: faculty.ksu.edu.sa
Heterocyclic Compounds • Heterocycles form the largest class of organic compounds. In fact, many natural products and most drugs contain heterocyclic rings. The colors of flowers and plants, antibiotics known to all as penicillins, compounds that transport the oxygen we breathe to our vital organs, and the components of DNA responsible for the genetic code are all heterocyclic compounds. From an organic chemist’s viewpoint, heteroatoms are atoms other than carbon or hydrogen that may be present in organic compounds. • The most common heteroatoms are oxygen, nitrogen, and sulfur. In heterocyclic compounds, one or more of these heteroatoms replaces carbon in a ring. The Criteria for Aromaticity and Hückel’s Rule • Aromatic heterocyclic compounds are those have a heteroatom in a ring and behave in a manner similar to benzene in some of their properties (i.e. react by electrophilic aromatic substitution). Further more, these compounds comply the criteria for Aromaticity and with the general rule proposed by Hückel. The Criteria for Aromaticity and Hückel’s Rule: 1. The compound must be cyclic (a ring of atoms). 2. The molecule is planar (all atoms in the molecule lie in the same plane) so that there is continuous or nearly continuous overlap of all p orbitals. 3. The molecule is fully conjugated (p orbital at every atom in the ring) (for C atoms to have p orbitals they must have double bonds, or bear a positive or negative charge i.e. ions) 4. The molecule has a closed loop of (4n+2) electrons in the cyclic arrangement of p orbitals, where n= 0, 1, 2, 3----integral number Aromatic heterocycles • Erich Hückel, a German physical chemist recognized in the early 1930s through MO calculations that cyclic planar molecules with a closed loop of 2,6,10,14,18,22……p- electrons in a fully conjugated system should be aromatic this finding is called the (4n+2) -electron rule. •Conversely, monocyclic planar molecules which fulfill all criteria except for Huckel’s rule; with 4n -electrons are classified as antiaromatic, e.g. cyclobutadiene •The compounds which doesn’t fulfil criteria for aromaticity are described as non aromatic, e.g. cyclopentadiene sp2 Hybridization of C, N, and O atoms • The atomic number of C is 6-electrons thus the electronic configuration is: 2 2 2 2 1s 2s 2p with 4 valence electrons, thus the sp hybridization will be as shown • 2 2 3 Similarly, N has 7-electrons thus the electronic configuration is : 1s 2s 2p with 5 valence electrons thus the sp2 hybridization will lead to presence of one lone pair of electrons occupies p-orbital 2 2 4 O has 8-electrons thus the electronic configuration is : 1s 2s 2p With 6 valence 2 electrons thus the sp hybridization will lead to presence of two lone pairs of electrons; one in p-orbital and the other in sp2 orbital Practice problem -1 2 Q1. Write down the electronic configuration of sp hybridized sulfur atom and conclude the number of lone pairs of electrons it posseses.
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