228x Filetype PPTX File size 0.24 MB Source: www.wsfcs.k12.nc.us
Sometimes we compare samples of different populations for certain characteristics. This data is often presented in a two way table. The test we use is a chi-square test of homogeneity. This is one of two similar chi-square tests, the other being a test for independence. Relapse Relapse Total No Yes Desipramine 14 10 24 Lithium 6 18 24 Placebo 4 20 24 Total 24 48 72 The data represent random samples of cocaine addicts treated with different drugs to reduce the likelyhood of a relapse. Are the proportion of addicts who relapse the same for each category? Step 1: H: The proportion of cocaine addicts who relapse 0 is the same for the different treatments. H: The proportion of cocaine addicts who relapse is not the a same for all treatments. Step 2: Assumptions: Our data are counts. We have random samples of the populations, as stated. c2 To find expected counts we enter the data in [A], run the test, and check [B]. é 14 10 ù o = A =ê ú [ ] [ ] ê 6 18 ú ê 4 20 ú é ù ë û ê 8 16 ú e = B = [ ] [ ] ê 8 16 ú ê 8 16 ú ë û All expected counts are more than 5. (o- e)2 Step 3: c2 =å =10.5 e Degrees of freedom are the number of rows minus 1 times the number of columns minus 1. df =(r- 1)(c- 1)=(3- 1)(2- 1)=2
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