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                            International Journal of Advanced Research and Publications 
                                                                                                     ISSN: 2456-9992                                                                            
                                                                                                                                                                            
                      Variation Of Parameters: Application To Electric 
                                                                           Circuit Analysis 
                                                                                                      
                                                                                      Engr. Dindo T. Ani 
                                                                                                      
                                                       Batangas State University, Electrical and Computer Engineering Department 
                                                                Alangilan, Batangas City, Philippines, PH-0063 950 394 5795 
                                                                                        dindoani@gmail.com 
                                                                                                      
                 Abstract:  This paper conducted a study on the application of variation of parameters as method in solving electric circuit analysis problems 
                 particularly the series combination of resistor, inductor and capacitor (RLC). The researcher wanted to explore the ideas of solving the 
                 second-order circuits using the method of variation of parameters as a user-friendly method which has been tested by the researcher. The 
                 paper tried to explain and discuss the method of variation of parameters in three distinct cases namely real and distinct roots, real and 
                 repeated roots, and complex and conjugate roots. The researcher exposed and expounded formulas and present variation of parameters in 
                 solving linear differential equation of second-order. The generalization of principles and concepts were established through examples. This 
                 study was able to derive the variation of parameters formula for electric circuit analysis specifically series resistor, inductor and capacitor. 
                 Results showed that the variation of parameters can be used as a method for solving series RLC electric circuit. 
                  
                 Keywords: differential equation, electric circuit, variation of parameters  
                  
                 1.  Introduction                                                                       focused on the method of variation of parameters, as well as 
                 Electric circuit analysis is one of the foundations of electrical                      the  applications  of  these  methods  to  series  RLC  circuit 
                 engineering.  Almost all branches of electrical engineering,                           (resistor-inductor-capacitor).  This  study  hopes  to  stimulate 
                 such  as  power  systems,  electrical  machines,  electronics,                         the  interest  of  students  toward  solving  electric  circuit 
                 control systems, are based on circuit theory. Thus, it can be                          analysis in different way. This can be used by instructors in 
                 said that basic circuit theory is considered as one of the most                        engineering  mathematics  and  electrical  engineering  as  an 
                 important subjects in electrical engineering curriculum. An                            additional  input  study  for  their  lectures.  This  can  also  be 
                 electric  circuit  is  determined  by  the  type  of  elements  it                     used by professionals as an alternative technique in solving 
                 contains and the manner in which the elements are connected                            differential equations and some circuit analysis. This study 
                 [1].  The  relationships  of  different  variables  related  to  the                   may also be helpful for future researchers as basis to study, 
                 analysis of circuits are expressed in the describing equations.                        analyze  and  expound  the  techniques  and  formulas  under 
                 The  describing  equations  for  resistive  circuits  are  simple                      study. This paper may be helpful not only to the students and 
                 algebraic  equations.  However,  the  circuits  are  not  only                         educators but also to those with knowledge and interest in 
                 resistive but inductive or capacitive in nature. The describing                        calculus especially engineering professionals. 
                 equations  for  these  types  of  circuits  are  differential  rather                      
                 than algebraic. The application of Kirchhoff’s Laws to these                           2.  Methodology 
                 networks gives rise to differential equations that, in general,                        This study is descriptive and expository in nature. The paper 
                 are  more  difficult  to  solve  than  algebraic  equations  [2,4].                    tried  to  explain  and  discuss  the  method  of  variation  of 
                 Most of the electrical engineering problems, especially the                            parameters. The researcher exposed and expounded formulas 
                 circuit analysis is governed or characterized by differential                          and  present  variation  of  parameters  in  solving  linear 
                 equations. This equation can be solved using the method of                             differential equation of second-order. The generalization of 
                 undetermined  coefficients.  For  the  differential  equation                          principles and concepts were established through examples. 
                 shown in equation 1, the method of undetermined coefficient                            It also discussed the related theorems and basic concepts to 
                 can be used [3].                                                                       aid understanding of the main concept. This research relied 
                   ( )            ( )           ( )          ( )                                        on books dealing with differential equations, differential and 
                                                        ( )  
                                                                                                        integral  calculus,  engineering  mathematics  and  electric 
                 The method of undetermined coefficients works only when                                circuit  analysis.  The  derivation  of  the  general  formula  for 
                 the coefficients a, b, and c are constants and the right-hand                          finding  the  relationships  between  the  variables  such  as 
                 term  f(x)  is  of  special  form,  i.e.  exponential,  polynomial,                    current,  voltage  and  time  was  shown.  The  electric  circuit 
                 sine,  cosine,  or  combinations.  If  these  restrictions  do  not                    problems were then solved using the method of variation of 
                 apply  to  a  given  nonhomogeneous  linear  differential                              parameters.  The  researcher  then  recorded,  compiled, 
                 equation,  then  a  more  powerful  method  of  determining                            synthesized  and  analyzed  the  gathered  information  as  the 
                 particular solution is needed, the method known as variation                           highlights of the study.    
                 of parameters [3,5]. In electrical engineering, the variation of                        
                 parameters  is  not  given  much  attention  on  books  and                            3.  Results and Discussion 
                 researches. This paper conducted a study on the application                            This  section  discusses  the  results  of  the  implemented 
                 of  variation  of  parameters  as  method  in  solving  electric                       methodology of the study. As shown in figure 1, the circuit is 
                 circuit analysis problems particularly the series combination                          composed  of  the  voltage  source,  resistor,  inductor  and 
                 of resistor, inductor and capacitor. The researcher wanted to                          capacitor. 
                 explore the ideas of solving the second-order circuits using 
                 the  method  of  variation  of  parameters  as  a  user-friendly 
                 method which has been tested by the researcher..  This study 
                                                                                           Volume 3 Issue 6, June 2019                                                            128 
                                                                                                             www.ijarp.org 
                              International Journal of Advanced Research and Publications 
                                                                                                                 ISSN: 2456-9992                                                                                                                
                                                                                                                                                                                                                     
                                                                                                                                  
                                                                                                                                 The first  step  is  to  construct  the  two  equations  needed  to 
                                                                                                                                 solve for A’(t) and B’(t) using equations 5 and 6. The two 
                                                                                                                                 equations are 
                                                                                                                                                                                         
                                                                                                                                                     ( )                      ( )         
                                                                                                                                                                                                          (  )  
                                                                                                                                  
                                                                                                                                                                                                           
                                                                                                                                                                                                        
                                                                                                                                        ( )                            ( )               
                                                                                                                                                                                                                             (  ) 
                                                                                                                                                                                 
                                               Figure 1: Series RLC Circuit                                                                                                                                 
                                                                                                                                 Then find A’(t) and B’(t) by solving equations 10 and 11 
                         By  applying  Kirchhoff’s  Voltage  Law  [2],  the  total                                               using Cramer’s rule, 
                                                                                                                                                                                                         
                     voltage is equal to the sum of the voltages across the resistor                                                                                                                   
                                                                                                                                                                        |                                      |
                     R, inductor L, and capacitor C. In equation form,                                                                                                                                       
                                                                                                                                                                                                       
                                                                                                                                                                                                      
                                            ( )            ( )            ( )
                                                                     ( )                                                                                    ( )
                                                                                                                                                                                                                  
                                                                                                                                                                                                       
                                                                                                                                                                                                    
                                                                                                                                                                          |                               |
                                                                                                                                                                                                    
                     By substituting the voltages in terms of their characteristics,                                                                                                               
                     the equation becomes 
                                                                                                                                                                                          
                                                                                                                                                                                                              
                                                ( )                                                                                                                       .                          /    
                            ( )                                                                                                                                                            
                                                           ∫ ( )                      ( ) 
                                                                                                                                                     ( )
                                                                                                                                                                                                                         
                                                                                                                                                                                                                    
                                                                                                                                                                (                                                     )
                                                                                                                                                                                                            
                                                                                                                                                                                                             
                     Differentiating and rearranging, the equation becomes 
                                                                                                                                                                                               
                                                                                                                                                                                               
                                                                                                                                                                               .                             /
                               ( )              ( )                                                                                                                                              
                                                                                                                                                        
                                                                                                                                                        ( )
                                                                       ( )                                                                                                                                            
                                                                                                               ( ) 
                                                                                                                                                                                                               
                                                                                                                                                                           (                                     )
                                                                                                                                                                                                                   
                                                                                                                                                                                                        
                     This  equation  (4)  is  a  second-order  linear  ordinary                                                                                                          
                                                                                                                                                                                         
                                                                                                                                                               ( )
                                                                                                                                                                                                               
                     differential  equation  with  constant  coefficients.  First  solve                                                                                           
                                                                                                                                                                                  (       )
                     for  the  complimentary  solution  of  the  homogeneous                                                                                                                             
                     differential equation                                                                                       The next step is to solve for the value of A(t) by integration. 
                                        ( )              ( )                                                                     The equation is 
                                                                                 ( )
                                                                                                 ( ) 
                                                                                                                                                                                        
                                                                                                                                                                                       
                                                                                                                                                          ( )
                                                                                                                                                             ∫                                                   
                                                                                                                                                                                  
                                                                                                                                                                                (       )
                     Using the quadratic formula to solve for the roots,                                                                                                                                
                                                                                                                                 Since V , ω, m , m , and L are constants, the equation will 
                                                                                                                                               m            1      2
                                                 √                                              ( )                              yield, 
                                                                           
                                                                                                                                                                       
                                                                                                                                                                                                 
                                                                                                                                                   ( )
                                                                                                                                                                                       ∫                          
                                                                                                                                                               (       )
                     For simplicity of solution, let                                                                                                                               
                                                                     ( )                                                         Use integration by parts to solve for A(t). The solution is 
                                                                                                                                 ∫           ∫      
                                                                                                                                  
                                                                    √                            
                                                                                                                                                                                       
                                                                                                                                                                                                        
                     From these roots, we have 3 possible cases.                                                                                                                                                  
                                                                                                                                                                                                  
                                                                                                                                                                                                      
                                                                                                                                                   
                     3.1 Real and Distinct Roots (Case 1)                                                                                ∫            
                     The roots are real and unequal if 
                                                                                                                                                                                                     
                                                                                                                                                                         (     )(                             )
                                                                                                                                                                                               
                                                                                                                                                                                                  
                                                                                                                                                                                         
                                                                                                                                                                                                      (                        )
                     The roots are                                                                                                                                       ∫(                        )             
                                                                                                                                                                                   
                                                                                                                                                                                      
                                                                                                                                  
                             √                
                                                     
                                                                                                                                                   
                                                                                                                                         ∫            
                                                                                                                                                                                   
                                                                                                                                                                                                 
                               √         
                                                                                                                                                                             
                                                                                                                                                                                
                                                                                                                                                                                             
                     The complementary solution of the homogeneous equation is                                                                                                    ∫                            (  ) 
                                                                                                                                                                             
                                                                                                                                                                                
                                                                                    
                                             ( )                                                                                  
                                                                                                 ( ) 
                                                                                                                                 Solving for  
                                                                                                                                           
                     Now, solve for the particular solution, i (t), using variation of                                           ∫              
                     parameters.                                                      p
                                                                                                                                  
                     The assumed value of ip(t) is                                                                               using integration by parts, 
                                                                                         
                                         ( )          ( )                    ( )         
                                                                                                     ( )                                                                                
                                        
                                                                                                      Volume 3 Issue 6, June 2019                                                                                             129 
                                                                                                                          www.ijarp.org 
                            International Journal of Advanced Research and Publications 
                                                                                                  ISSN: 2456-9992                                                                    
                 
                                                                                                                                                                  
                                                                                                                                     (                               )
                                                                                                                                                       
                                                                                                                                            
                                                                                                         ( )
                                                                                                                                    6                                  7   
                                                                                                                                                              
                                                                                                                    (             )           (    )
                                                                                                                                                    
                                                                                                                                                   
                      ∫                                                                           Then solve for B’(t) using Cramer’s rule, 
                                                                                                                                       
                                                                                                                                                     
                                                 (        )              
                                                      (                    )
                                                                                                                               |                      |
                                                                                                                                                  
                                                                                                                                      
                                                                                                                                                     
                                                                                                                      ( )
                                                                                                                                                               
                                                                     (               )                                                                 
                                               ∫(                 )                                                                                    
                                                                                                                                                   
                                                                                                                                 |                       |
                                                                                                                                                      
                                                                                                                                                   
                                                        
                     ∫                                                                                                                          
                                                                                                                                             
                                                                                                                             (    ).                   /   
                                                                                                                                                
                                                                                                                 ( )
                                                                                                                                                                    
                                                                                                                                                                
                                                     ∫                        (  )                                       (                       )
                                                                                                                                                            
                                                
                                                   
                                                                                                                                                   
                                                                                                                                                
                Then substitute equation 13 to equation 12,                                                                      (    ).                  /
                                                                                                                                                   
                                                                                                                   ( )
                                                                                                                                                                  
                                                                                                                                                              
                                                                                                                            (      )(                          )
                                                                                                                                                      
                          ∫                                                                                                                               
                                                                                                                                              
                                                                                                                                           
                                                                                                                                              
                                                                                                                          ( )
                                                                                                                                                            
                                                                                                                                       
                                                                                                                                        (      )
                                                                                                                                                       
                                                         [                   
                                                       
                                                                                                  Then solve for B(t) using integration by parts. The equation 
                                                                  
                                                         ∫                   ]                    is 
                                                     
                                                        
                                                                                                                                             
                                                                                                                                          
                                                                                                                     ( )                     
                                                                                                                         ∫                                    
                                                                                                                                      
                        ∫                                                                                                              (              )
                                                                                                                                               
                                                                                                                                                      
                                                          
                                                                                                  Since V , ω, m , m , and L are constants, the equation is now 
                                                                                                           m        1    2
                                                    
                                                                                                                                
                                                                                                                                                   
                                                                                                                ( )
                                                                                                                                          ∫                     
                                                                                                                          (            )
                                                                                                                               
                                                  (     )                                                                              
                                                     
                                                                                                   
                                                       
                                                                    
                                                            ∫                                     Solving for  
                                                  (     ) 
                                                     
                                                                                                                                     
                                                                                                                            ∫             
                Combining similar terms, the equation will yield                                   
                                                                                                  using integration by parts, 
                                                                      
                        ∫                                    ∫                  
                                                            
                                                    (    )
                                                                                                                                                   
                                                         
                                                                                                                                                    
                                                                                                                                                             
                                                                                                                                                                 
                                                                                                                                                   
                                                                                                                                                     
                                                                                                   
                                                                          
                                                          
                                                  (  )                                                                                             
                                                                                                                                                            
                                                                                                                                    (         )              
                                                                                                       ∫                              (                       )
                                                                                                                                                   
                            6              7∫            
                                   (    )                                                                                               
                                     
                                                                                                                                                 
                                                                                                                                                     (                  )
                                                                                                                                ∫(                 )             
                                                                                                                                       
                                                                                                                                          
                                                       
                                                          
                                                                                                                                     
                                                                                                                                              
                                                                                                      ∫                                               
                                                              
                                                      (  )                                                                          
                                                                                                                                       
                                                                                                                                               
                         ∫                                                                                                            ∫                           (  ) 
                                                                                                                                   
                                                                                                   
                                                                              
                                                        (    ) 
                                                          
                                                                                                  Solving for 
                                                           
                                                                                                                                     
                                               [              ]                                                             ∫              
                                                       (  )
                                                                                                   
                Simplifying, the equation becomes                                                 using integration by parts, 
                                                      
                                                       (                                )
                                                                         
                                                                                                                                                    
                    ∫                                                                     
                                                            (  )                                                                                    
                                                                                                                                                             
                                                                                                                                                                
                Therefore,                                                                                                                          
                                              
                                                                  
                              ( )                                 
                                                         ∫                   
                                        (      )
                                                      
                                                                                        Volume 3 Issue 6, June 2019                                                     130 
                                                                                                          www.ijarp.org 
                          International Journal of Advanced Research and Publications 
                                                                                           ISSN: 2456-9992                                             
                                                                                                                                        
                                                                                  
                   ∫                                                             Combining similar terms and simplifying, 
                                                                                                                (               )
                                                                                                                    
                                         (       )           
                                              (               )                           ( )
                                                                                                               6
                                                                                                                                    
                                                                                                   (          )       (    )
                                                                                                                            
                                                                                                                           
                                                                                                              (                          )
                                                       (               )                                                        
                                       ∫(              )                                                                                  7  
                                                                                                                     (    )        
                                                                                                                            
                          
                  ∫                                                               
                                                                                 Since 
                                               
                                                                                                       ( )      ( )      ( )
                                                                                                                        
                                                                                                                         
                                                                                  
                                                    
                                            ∫                       (  )         then 
                                                                                                            
                                                                                   ( )                      
                                                                                                       
                                                                                                        
                                                                                                                       (               )
             Substituting equation 15 to equation 14,                                                                 6     
                                                                                                          (          )       (    )        
                                                                                                                                    
                                                                                                                                  
                                                        
                      ∫                                                                                  (                          )
                                                                                                                          
                                                                                                                                     7   (  ) 
                                                                                                                (   )        
                                                                                                                       
                                                           
                                                [                                 
                                                 
                                                                                                                              
                                                ∫                ]                                                                  
                                                                                                                         √             
                                                                                                                               
                                                                                                                                     
                                                                                                                         
               ∫                                                                                                               
                                                                                                           √                     
                                                              (  )                                                       
                                                                                                                               
                                                     
                                             ∫                                    
                                     (    ) 
                                                                                 To verify the validity of this equation, let us use this equation 
             Combining similar terms,                                            in an example. 
                                                                                  
                                            
                                                                                 Example 1. Suppose the given circuit parameters are:  
                ∫                                ∫                 
                                         (  )                                    R = 10 Ω, L = 1 H, C = 1/16 F, V  = 10 V, ω = 2 rad/s 
                                                                                                                     m
                                                                                 The first step is to determine in what case the circuit belongs.  
                                                                          
                                                             (   )                                                  
                                                                                                                    
                                                                                                                 ( ) 
                                                                                                                  
                         
                                                                                                                  
                6           7∫                                                                                              
                            
                      (  )                                                                                          
                                                                                                             ( )
                                                                                                                .     /
                                                                                                                     
                                                                                                                  
                                                             (   )                                                       
                                                                                                                              
                                                                                                                  
                                                                                 then this falls under case 1.           
                                                                 
                                                                          
                                                                                  
                                                              (  )
              ∫                                                                  Therefore, equation 16 must be used as shown below. 
                                                            
                                                                                                            
                                                   [           ]                   ( )                      
                                                                                                       
                                                        (  )                                            
                                                                                                                       (               )
                                                                                                                            
                                                                                                                      6                    
                                                                                                          (          )       (    )
             Simplifying,                                                                                                           
                                                                                                                                  
                                             
                                              (                           )
                                                                                                         (                          )
                                                                                                                          
               ∫                                                                                                                     7 (  ) 
                                                                                                                             
                                                   (  )                                                         (   )
                                                                                                                       
             Therefore,                                                           
                                                                                 The next step is to determine the roots, 
                                       
                                                       
                          ( )                                                                                                 
                                                ∫                                                                                     
                                  (     )                                               √                              √                   
                                                                                                                               
                                                                                                                  ( )       ( )
                                                                                                                                   ( )
                                                                                                                                      . /
                                                                                                                                        
                                       
                                           (                          )
                                                                                                                             
                                                                                                                           
                    ( )
                                          6                            7  
                             (          )         (    )                           
                                                        
                                                                                 then plug-in the values to equation 16 to get 
                                                                                   ( )                      
             After solving for A(t) and B(t), substitute to i (t),                                     
                                                            p                                           
                                                                                                           ( )(   )     (                       )
                               ( )     ( )           ( )                                                                                 
                                                               
                                                                                                                       6
                                                                                                         ( )(        )       (   )     ( ) 
                                                                                                                                     
                  
                                 
                                                                                                         (                     )
                                     (                )                                                                   
                                                                         
                  8                 6                            79                                                             7  
                                                                                                                            
                                                                                                             (   )     ( )
                      (           )         (   )                                                                    
                                                  
                                                
                                 
                                     (                          )                 
                                                       
                                                                         
                   8                6                            79              Combining similar terms and simplifying, 
                       (          )         (    )        
                                                  
                                                                                                             
                                                                                    ( )
                                                                                                                                         
                                                                                                         
                                                                                 Volume 3 Issue 6, June 2019                                131 
                                                                                                 www.ijarp.org 
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...International journal of advanced research and publications issn variation parameters application to electric circuit analysis engr dindo t ani batangas state university electrical computer engineering department alangilan city philippines ph dindoani gmail com abstract this paper conducted a study on the as method in solving problems particularly series combination resistor inductor capacitor rlc researcher wanted explore ideas second order circuits using user friendly which has been tested by tried explain discuss three distinct cases namely real roots repeated complex conjugate exposed expounded formulas present linear differential equation generalization principles concepts were established through examples was able derive formula for specifically results showed that can be used keywords introduction focused well is one foundations applications these methods almost all branches hopes stimulate such power systems machines electronics interest students toward control are based theory...

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