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Math 20F Linear Algebra Lecture 19 1
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Determinants (Sec. 3.2)
Slide 1 • Review: Definition of determinant of n×n matrices.
• Properties of determinants.
• Determinants and elementary row operations.
• Determinant of a product of matrices.
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Review: Definition of determinant
Definition 1 The determinant of an n×n matrix A = [aij is
Slide 2 given by
n
det(A) = X(−1)1+jdet(A1j)a1j.
j=1
This formula is called “expansion by the first row.”
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Math 20F Linear Algebra Lecture 19 2
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Properties
Theorem 1 (Main properties of n×n determinants) Let
A=[a1,···,an] be an n×n matrix. Let c be an n-vector.
• det([a1,···,aj +c,···,an]) = det([a1,···,aj ···,an])
+det([a1,···,c,···,an]).
Slide 3 • det([a1,···,caj,···,an]) = cdet([a1,···,aj,···,an]).
• det([a1,···,ai,···,aj,···,an]) =
−det([a1,···,aj,···,ai,···,an]).
• det([a1,···,ai,···,ai,···,an]) = 0.
• det(A) = det(AT).
• {a1,···,an} are l.d. ⇔ det([a1,···,an]) = 0.
• A is invertible ⇔ det(A) 6= 0.
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Properties
The properties of the determinant on the column vectors of A and
the property det(A) = det(AT) imply the following results on the
rows of A.
Theorem 2 (Determinants and elementary row operations)
Slide 4 Let A be a n×n matrix.
• Let B be the result of adding to a row in A a multiple of
another row in A. Then, det(B) = det(A).
• Let B be the result of interchanging two rows in A. Then,
det(B) = −det(A).
• Let B be the result of multiply a row in A by a number k.
Then, det(B) = kdet(A).
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Math 20F Linear Algebra Lecture 20 3
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Determinant and elementary row operations
Theorem 3 If E represents an elementary row operation and A is
an n×n matrix, then
det(EA) = det(E)det(A).
Slide 5
The proof is to compute the determinant of every elementary row
operation matrix, E, and then use the previous theorem.
Theorem 4 (Determinant of a product) If A, B are arbitrary
n×nmatrices, then
det(AB) = det(A)det(B).
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✬ Determinantofaproduct of matrices ✩
Proof: If A is not invertible, then AB is not invertible, then the
theorem holds, because 0 = det(AB) = det(A)det(B) = 0. Suppose
that A is invertible. Then there exist elementary row operations
Ek,···,E1 such that
A=Ek···E1.
Slide 6 Then,
det(AB) = det(Ek···E1B),
= det(Ek)det(Ek−1···E1B),
= det(Ek)···det(E1)det(B),
= det(Ek···E1)det(B),
= det(A)det(B).
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Math 20F Linear Algebra Lecture 20 4
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Formula for the inverse matrix
Slide 7 • Formula for the inverse matrix.
• Application to systems of linear equations.
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Formula for the inverse matrix
Theorem 5 Let A be an n×n matrix with components
(A)ij = aij. Let Cij = (−1)i+j det(Aij) be the ijth cofactor, and
∆=det(A). Then the component ij of the inverse matrix A−1 is
given by
Slide 8 A−1ij = 1 [Cji].
∆
That is,
C11 C21 · · · Cn1
C C · · · C
−1 1 12 22 n2
A = . . . .
∆ . . .
. . .
C1n C2n ··· Cnn
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