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Math 221
Week 4 part 2
Trigonometric functions:
limits and derivatives
Please take a moment to just breathe.
We define sinθ, cosθ, and tanθ using the unit circle.
Note that by similar triangles, tanθ = sinθ
In this section:
1 cosθ
We review the trigonometric functions.
We prove that lim sinh = 1.
h→0 h
We derive the derivative of several trigonometric functions.
1 sinθ tanθ
θ cosθ
We will show that
To compute the derivatives, we will need the following limits.
d lim sinh = 1 lim cos h − 1 = 0
dt sin t = cos t .
h→0 h h→0 h
As evidence of the first limit, recall that the arc of a unit circle
of angle θ has length θ. The line segment representing sinθ
appears to have nearly the
position of the mass:
same length as the bit of arc.
p(t) = sin t
velocity of the mass:
p′( t) = cos t
Proof using Squeeze Theorem that lim sinh = 1.
+ h
h→0
For h in the interval [0, π/2],
The proofs that
sinh ≤ h ≤ tanh, so
lim sinh = 1 and lim cosh − 1 = 0
h 1 h→0− h h→0 h
1 ≤ sinh ≤ cosh
are similar.
By the Squeeze Theorem, since lim 1 =1,
We will also need these formulas:
h h→0+ cosh
lim =1.
sin(x + h) = sin xcosh + cosxsinh
+ sinh
h→0 cos(x + h) = sin xsinh − cosxcosh
We have
Use the limit definition to compute the derivative of sin x:
d sinx = cosx
d sin(x + h) − sin x dx
dx sinx = lim h
and a similar computation shows
h→0
=lim sinxcosh+cosxsinh−sinx
d cosx = −sinx
h→0 h dx
=lim sinxcosh−sinx+cosxsinh
Exercise: compute d tan x using the quotient rule.
h→0 h dx
=lim[sinxcosh−1 +cosxsinh] = cosx (Please pause the video and try it yourself!)
h→0 h h
Trigonometric functions and their derivatives.
d tanx = d [sinx]
dx dx cosx sin x cos x
tan x sec2 x
= (sinx)′( cosx) − (sin x)(cosx)′
secx sec x tan x
cos2x cosx −sin x
cot x −csc2 x
= (cosx)(cosx)−(sinx)(−sinx)
cscx −csc x cot x
cos2x
If a trigonometric function starts with “co”, then its derivative
2 2 has a negative sign.
= (cosx) +(sinx) = 1 =sec2x Please memorize these.
cos2x cos2x
A side note about lim sinh = 1
h→0 h
In practice, the approximation sinh ≈ h for small h is very
useful.
If we want to speed up the oscillation, we also have
lim sin(2h) = 1, etc.
h→0 2h
Here is the full “Taylor series” for sin x from Calc II.
sinh = h−h3/3!+h5/5!−h7/7!−h9/9!+....
The more terms you take, the better the approximation will be.
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