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Fundamental Theorem of Calculus,
Riemann Sums, Substitution Integration Methods
104003 Differential and Integral Calculus I
Technion International School of Engineering 2010-11
Tutorial Summary – February 27, 2011 – Kayla Jacobs
Indefinite vs. Definite Integrals
A calc student upset as could be
· Indefinite integral: That his antiderivative didn't agree
With the one in the book
The function F(x) that answers question: E'en aft one more look.
Oh! Seems he forgot to write the "+ C".
“What function, when differentiated, gives f(x)?” -Anonymous
· Definite integral:
o The number that represents the area under the curve f(x) between x=a and x=b
o a and b are called the limits of integration.
o Forget the +c. Now we’re calculating actual values .
Fundamental Theorem of Calculus (Relationship between definite & indefinite integrals)
If
and f is continuous, then F is differentiable and
.
Important Corollary: For any function F whose derivative is f (i.e., ’ ),
&
%
&
This lets you easily calculate definite integrals!
Definite Integral Properties
· 0
·
· whether or not ,
Area in [a,b] Bounded by Curve f(x)
Case 1: Curve entirely above x-axis. Really easy! Area =
Case 2: Curve entirely below x-axis. Easy! Area = | | = -
Case 3: Curve sometimes below, sometimes above x-axis. Sort of easy! Break up into sections.
Average Value
The average value of function f(x) in region [a,b] is:
average
Calculus – Tutorial Summary – February 27,, 22001111 2
Riemann Sum
Let [a,b] == cclloosseedd iinntteerrvvaall iinn tthhee ddoommaaiinn ooff ffuunnccttiioonn f
PPaarrttiittiioonn [[aa,,bb]] iinnttoo nn ssuubbddiivviissiioonnss:: {{ [[xx ,x ], [x ,x ], [x ,x ], … , [x ,x ]} where a == xx < x < … < x < x = b
0 1 1 2 2 3 n-1 n 0 1 n-1 n
The Riemann sum ooff ffuunnccttiioonn ff oovveerr iinntteerrvvaall [[aa,,bb]] iiss::
1
* + , ·
-20 - - -/0
th
where y is any value between x aanndd xx. Note (x – x ) is the length of the i ssuubbddiivviissiioonn [[xx , x].
i i-1 i i i-1 i-1 i
If for all i: then…
y = x S = Left Riemann sum
i i-1
y = x S = Right Riemann sum
i i
y = (x + x )/2 S = Middle Riemann sum
i i i-1
f(yi) = ( f(x ) + f(x) )/2 S = Trapezoidal Riemann sum
i-1 i
f(y) = maximum of f over [x , x] S = Upper Riemann sum
i i-1 i
f(y) = minimum of f over [x , x] S = Lower Riemann sum
i i-1 i
As ' ( ∞, S ccoonnvveerrggeess ttoo tthhee vvaalluuee ooff tthhee ddeeffiinniittee iinntteeggrraall of f over [a,b]: lim *
1((6
Ex: Riemann sum methods of f(x)) == x3 over interval [a, b]] == [[00,, 22]] uussiinngg 44 eeqquuaall ssuubbddiivviissiioonnss ooff 00..55 eeaacchh::
(1) Left Riemann sum: (2) Right Riemann sum:
(4) Middle Riemann sum: (3) TTrraappeezzooiiddaall RRiieemmaannnn ssuumm::
Calculus – Tutorial Summary – February 27, 2011 3
Integration Method: u-substitution
%7·7 %977
9
…where 7 7’ (because 7’ 7/).
Notes:
· This is basically derivative chain rule in reverse.
· The hard part is figuring out what a good u is.
· If it’s a definite integral, don’t forget to change the limits of integration! ( 7, ( 7
· If it’s an indefinite integral, don’t forget to change back to the original variable at the end, and +c.
Basic Trigonometric Derivatives and Indefinite Integrals
From trigonometric identities and u-substitution:
Calculus – Tutorial Summary – February 27, 2011 4
Integration Method: Trigonometric Substitution for Rational
Functions of Sine and Cosines
To integrate a rational function of sin(x) and cos(x), try the substitution:
@ tan 2 @
2 1@?
Use the following trig identities to transform the function into a rational function of t:
2 tan 2@
sin 2 ?
1tan?2 1@
1tan?CD 1@?
2
cos 1tan?CD1@?
2
2tanC2D 2@
tan 1tan?CD1@?
2
Integration Method: Trigonometric Substitution
If the integral involves… … then substitute… … and use the trig identity…
E E 7 · sinG ? ?
F 1sin G cos G
E E 7 · tanG ? ?
F 1tan G sec G
E E 7 · secG ? ?
F sec G1 tan G
Steps:
1. Notice that the integral involves one of the terms above.
2. Substitute the appropriate u. Make sure to change the dx to a du (with relevant factor).
3. Simplify the integral using the appropriate trig identity.
4. Rewrite the new integral in terms of the original non-Ѳ variable
(draw a reference right-triangle to help).
5. Solve the (hopefully now much easier) integral,
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