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GEOMETRICPROGRESSION Examples The following are called geometric progressions: 1. 3, 6, 12, 24, ··· 2. 1, −1/3, 1/9, −1/27, ··· 3. a, ar, ar2, ar3 ···. Wenote that the ratio between any two consecutive terms of each of the above sequences is always the same. 1. 6/3 = 12/6 = 24/12 = ··· = 2. 2. −1/3 = 1/9 = −1/27 = ··· = −1/3. 1 −1/3 1/9 3. ar/a = ar2/ar = ar3/ar2 = ··· = r. The ratios that appear in the above examples are called the common ratio of the geometric progression. It is usually denoted by r. The ¯rst term (e.g. 3, 1, a in the above examples) is called the initial term, which is usually denoted by the letter a. Example Consider the geometric progression a, ar, ar2, ar3, ···. The third, sixth and twentieth terms of the progression are given by ar2, ar5 and ar19 respectively. The pth term is given by arp−1. GEOMETRICSERIES The sum of the geometric progression a, ar, ar2, ar3, ···, denoted by Sn = a+ar+ar2+···arn−1, is called the geometric series. Multiplying the above geometric series by r, and then subtracting the resulting series by the geometric series gives S −rS =a−arn. n n So we obtain µ ¶ 1−rn S =a . n 1−r 1 Example Find the sum of the ¯rst seven terms of the sequence 2/3, −1, 3/2,···. The common ratio is −3/2. Thus µ ¶ µ ¶ µ ¶ µ ¶ 2 3 3 2 3 3 3 4 3 5 S7 = 3 −1+ 2 − 2 + 2 − 2 + 2 2/3(1−(−3/2))7 = 1−(−3/2)) ˙ µ ¶ = 22 1+2178 53 128 = 1153. 240 Example Find the sum of the ¯rst n terms of the sequence 1, 1, 1 , 1 , ···. 2 3 2 2 2 We note that the ¯rst term a = 1 and the common ratio is clearly 1/2. So by the geometric series formula µ ¶ n Sn = 1−(1/2) =2 1− 1 . 1−1/2 2n n Remark Notice that the term 1/2 can be made arbitrary small by choosing the n su±ciently large. Exercises Find the sum of the ¯rst 1. seven terms of 1, 1, 2,···. (2059) 2 3 9 1458 2. six terms of −2, 21, −31,···. ( 1281) 2 8 512 3. eight terms of 3, 11, 3,···. ( 1911). 4 2 4 4. ten terms of 2, −4, 8, ···. ( −682) 5. seven terms of 16.2, 5.4, 1.8,···. ( 1093) 45 6. p terms of 1, 5, 25,···. ( 5p−1) 4 7. 2n terms of 3, −4, 16,···. ( 9(1−(4)2n) 3 7 3 √ √ 8. twelve terms of 1, 3, 3,···. ( 364( 3+1)) 2
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