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picture1_Geometry Pdf 168107 | 02 Geo Revisited


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File: Geometry Pdf 168107 | 02 Geo Revisited
red mop lecture june 20 2002 po shen loh 1 common abbreviations for geometry problems given triangle abc a b and c are the lengths of the sides opposing vertices ...

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                                        Red MOP Lecture: June 20, 2002.
                                                   Po-Shen Loh
             1    Common abbreviations for geometry problems
             Given triangle ABC:
                • a, b, and c are the lengths of the sides opposing vertices A, B, and C, respectively.
                • s is the semiperimeter
                • r is the inradius
                • R is the circumradius
             2    Facts, Part I
                1. Extended Law of Sines a/sinA = 2R.
                2. [ABC] = abc/4R.
                3. (Geometry Revisited, page 3.) Let p and q be the radii of two circles through A, touching BC at B
                  and C, respectively. Then pq = R2.
                4. Ceva Given triangle ABC. Let D ∈ BC, E ∈ CA, and F ∈ AB. Suppose that:
                                                   AF BDCE =1.
                                                   FBDCEA
                  Prove that AD, BE, and CF are concurrent.
                5. Trig Ceva Given triangle ABC. Let D ∈ BC, E ∈ CA, and F ∈ AB. Suppose that:
                                             sinCADsinABEsinBCF =1.
                                             sinDABsinEBC sinFCA
                  Prove that AD, BE, and CF are concurrent.
                6. Prove that the centroid of a triangle lies 2/3 of the way down each median.
                7. Steiner-Lehmus Let ABC be a triangle such that the lengths of two angle bisectors are equal. Prove
                  that ABC is isosceles.
                8. (Geometry Revisited, page 13.) Prove that abc = 4srR.
                9. (Geometry Revisited, page 13.) Let ra, rb, and rc be the radii of the three excircles of triangle ABC.
                  Prove that 1/r = 1/r +1/r +1/r .
                                   a    b     c
               10. Orthic Triangle The feet of the altitudes of triangle ABC determine a triangle, called the orthic
                  triangle. Prove that the orthocenter of ABC is the incenter of that triangle.
               11. Euler Line Let O, G, and H be the circumcenter, centroid, and orthocenter of ABC, respectively.
                  Prove that O, G, and H are collinear, and that HG = 2GO.
                                                       1
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...Red mop lecture june po shen loh common abbreviations for geometry problems given triangle abc a b and c are the lengths of sides opposing vertices respectively s is semiperimeter r inradius circumradius facts part i extended law sines sina revisited page let p q be radii two circles through touching bc at then pq ceva d e ca f ab suppose that af bdce fbdcea prove ad cf concurrent trig sincadsinabesinbcf sindabsinebc sinfca centroid lies way down each median steiner lehmus such angle bisectors equal isosceles srr ra rb rc three excircles orthic feet altitudes determine called orthocenter incenter euler line o g h circumcenter collinear hg go...

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